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Sever21 [200]
2 years ago
7

A shell is launched with an initial velocity at an angle of 40.0° above horizontal

Physics
1 answer:
olasank [31]2 years ago
7 0

Answer:

122.17 m/s

Explanation:

x cos 40 = horizontal velocity

1500 m / x cos 40   = time in the air =<u> 1958.11 / x</u>

x sin 40 = vertical velocity

 find when shell vertical velocity = 0 (this is max height....1/2 way through its flight)  , the time when it hits the ground will be twice this...  

   0 =  x sin 40 - 9.8 t

  t =  x sin40 / 9.8        time in the air is twice this = .13118<u> x</u>

<u />

Equate the two times from above to solve for x

1958.11/ x  =  .13118 x

x = 122.17 m/s

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Force = pressure × area

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F = 1,780,000 N

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Answer:

41.2°

Explanation:

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3 years ago
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A blue line with 5 orange tick marks then one red tick mark then 4 orange tick marks. The number zero is above the red tick mark
Natali5045456 [20]

The total displacement of the toy car at the given positions is 0.

The given parameters;

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The total displacement of the car is calculated as follows;

  • <em>Let the </em><em>left </em><em>direction be "</em><em>negative </em><em>direction"</em>
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\Delta x = - \ 5\ cm  \ + \ 8 \ cm \ - \ 3 \ cm \\\\\Delta x = 0

Thus, the total displacement of the toy car at the given positions is 0.

Learn more about displacement here: brainly.com/question/18158577

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