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2 years ago

A shell is launched with an initial velocity at an angle of 40.0° above horizontal

Physics

1 answer:

olasank [31]2 years ago

7 0

Answer:

122.17 m/s

Explanation:

x cos 40 = horizontal velocity

1500 m / x cos 40 = time in the air = 1958.11 / x

x sin 40 = vertical velocity

find when shell vertical velocity = 0 (this is max height....1/2 way through its flight) , the time when it hits the ground will be twice this...

0 = x sin 40 - 9.8 t

t = x sin40 / 9.8 time in the air is twice this = .13118 x

Equate the two times from above to solve for x

1958.11/ x = .13118 x

x = 122.17 m/s

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g100num [7]

Answer:

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4. Crystalline

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Explanation:

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4. Most minerals will grow into a crystal shape, space permitting. Mineral deposits are often small because there is usually a variety of minerals in the same vicinity competing for the same room to grow. A mineral’s crystalline structure determines its hardness, cleavage (how it breaks) and color. There are six different crystal shapes: cubic, tetragonal, orthohombic, hexagonal, monoclinic and triclinic.

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4 0

2 years ago

Two large thin metal plates are parallel and close to each other. On their inner faces, the plates have excess surface charge of

wariber [46]

Answer:

For left = 0 N/C

For right = 0 N/C

At middle = $-7.6836 * 10^{-11} \vec{i}$ N/C

Explanation:

Given data :-

б = $6.8 * 10^{-22}$ C/ m²

Considering the two thin metal plates to be non conducting sheets of charges.

Electric field is given by

$E = \frac{\sigma }{2\varepsilon }$

1) To the left of the plate

$\vec{E}= (\frac{\sigma }{2\varepsilon })(-\vec{i})+ (\frac{\sigma }{2\varepsilon })(\vec{i})$ = 0 N/C.

2) To the right of them.

$\vec{E}= (\frac{\sigma }{2\varepsilon })(-\vec{i})+ (\frac{\sigma }{2\varepsilon })(\vec{i})$ = 0 N/C.

3) Between them.

$\vec{E}= (\frac{\sigma }{2\varepsilon })(-\vec{i})+ (\frac{\sigma }{2\varepsilon })(-\vec{i})$ = $(\frac{\sigma }{\varepsilon })(-\vec{i})$ = $-\frac{6.8 * 10^{-22} }{8.85 * 10 ^{-12} } \vec{i}$ = $-7.6836 * 10^{-11} \vec{i}$ N/C