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4 years ago

6

Doreen Samuels trip across the country she traveled 2,884 miles. her trip took 7 Days .find out the unit rate represent the aver

age mile she traveled per day during the trip

1 answer:

stealth61 [152]4 years ago

6 0

<span>Average ?

2884 : 7 = 412 miles / day</span>

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A gold alloy contains 15 milligrams of gold for every 4 milligrams of copper. A jeweler uses 48 milligrams of copper to make the

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There are 180 milligrams of gold in the alloy

Step-by-step explanation:

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3 years ago

What facts are required in order to conclude that m∠ADE = m∠ABC?

mariarad [96]

Answer:

The correct option is;

DE = 2·(BC), AD = 2·(AB), and AE = 2·(AC)

Step-by-step explanation:

Given that we have;

1) The side AD of the angle m∠ADE corresponds to the side AB of the angle m∠ABC

2) The side DE of the angle m∠ADE corresponds to the side BC of the angle m∠ABC

3) The side AE of the angle m∠ADE corresponds to the side AC of the angle m∠ABC

Then when we have DE = 2·(BC), AD = 2·(AB), and AE = 2·(AC), we have by sin rule;

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m∠ADE) = m∠ABC).

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3 years ago

The local animal shelter throws a dog-themed party. Humans, h, and dogs, d are both invited. The event space imposes two restric

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3 years ago

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What reason should kamal add to all of the question marks in order to completer the proof

brilliants [131]

Answer: The answers is alternate interior angles.

Step-by-step explanation: First of all, the questions marks given in the figure are renamed in the attached figure as (a), (b), (c) and (d).

For (a): Since AC is parallel to A'C' and A'D is a transversal for these two parallel lines, so, ∠CDB' = ∠B'A'C', because these are alternate interior angles.

For (b): Since BC is parallel to B'C' and A'B' is a transversal, so ∠BEB' = ∠A'B'C', because these are alternate interior angles.

For (c): Since AB is parallel to A'B' and AD is a transversal, so ∠BAC = ∠CDB', because these are alternate interior angles.

For (d): Since AB is parallel to A'B' and BE is a transversal, so ∠ABC = ∠BEB', because these are alternate interior angles.

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3 years ago

A manufacturer of college textbooks is interested in estimating the strength of the bindings produced by a particular binding ma

IrinaVladis [17]

Answer:

538 books should be tested.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.99}{2} = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.005 = 0.995$ , so $z = 2.575$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

How many books should be tested to estimate the average force required to break the binding to within 0.08 lb with 99% confidence?

n books should be tested.

n is found when $M = 0.08$

We have that $\sigma = 0.72$

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.08 = 2.575*\frac{0.72}{\sqrt{n}}$

$0.08\sqrt{n} = 2.575*0.72$

$\sqrt{n} = \frac{2.575*0.72}{0.08}$

$(\sqrt{n})^{2} = (\frac{2.575*0.72}{0.08})^{2}$

$n = 537.1$

Rounding up

538 books should be tested.

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3 years ago