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alexdok [17]
3 years ago
11

Can u help me with this question please

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
6 0

Answer:

C, 2x + 22

Step-by-step explanation:

Its just simple combining like terms

3x-x=2x, 10+12=22

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(8•365)•35 is the correct answer because 8 hrs of sleep each day times 365 days in a year = 2920 hrs slept in one year. Now you must take 2920 and multiply it by the 35 years she has been alive to get 102,200 hrs of sleep.
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Jeremy is going to roll a fair 6 sided die 180 times.
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What is the general form of the equation for the given circle centered at o(0, 0)? a. x2 y2 41 = 0 b. x2 y2 − 41 = 0 c. x2 y2 x
Tasya [4]

The general form of the equation for the given circle centered at o(0, 0) is x² + y² - 41 = 0.

According to the question,

The general form of the equation for the given circle centered at o(0, 0) is (x-h)² + (y-k)²  = r².

  • The given equation is x² + y² - 41 = 0 which is also represented by

        (x-0)² + (y-0)²  = -(√41)². This is not possible.

  • The given equation is x² + y² - 41 = 0 which is also represented by (x-0)² + (y-0)²  = (√41)²This means that the circle is centered at (0,0). Thus, the equation is correct
  • The given equation is x² + y² +x+ y- 41 = 0 which is also represented by (x+1/2)² + (y+1/2)²  = (√(83/2))²This means that the circle is centered at (-1/2,-1/2). Thus, this equation is incorrect.
  • The given equation is x² + y² +x- y- 41 = 0 which is also represented by (x+1/2)² + (y-1/2)²  = (√(83/2))²This means that the circle is centered at (1/2,-1/2). Thus, this equation is incorrect.

Hence, the general form of the equation for the given circle centered at o(0, 0) is x² + y² - 41 = 0.

Learn more about circle here

brainly.com/question/14338946

#SPJ1

3 0
2 years ago
-7x+8y=-18, 4x-9y=-3 Solve the system of equations
Gennadij [26K]

Answer:

\large\boxed{x=6,\ y=3\to(6,\ 3)}

Step-by-step explanation:

\left\{\begin{array}{ccc}-7x+8y=-18&\text{multiply both sides by 4}\\4x-9y=-3&\text{multiply both sides by 7}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}-28x+32y=-72\\28x-63y=-21\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad-31y=-93\qquad\text{divide both sides by (-31)}\\.\qquad\qquad\boxed{y=3}\\\\\text{Put the value of y to the second equation}\\\\4x-9(3)=-3\\4x-27=-3\qquad\text{add 27 to both sides}\\4x=24\qquad\text{divide both sides by 4}\\\boxed{x=6}

8 0
3 years ago
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