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Colt1911 [192]
3 years ago
8

Find the surface area of the figure. A. 80 square inches B. 280 square inches C. 300 square inches D. 21 square inches?

Mathematics
1 answer:
mars1129 [50]3 years ago
4 0
The answer is D. for sure 21 square inches
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What is the measure of ABC?
MaRussiya [10]

Answer:

D i think

Step-by-step explanation:

3 0
3 years ago
3n-5=19
alina1380 [7]

Answer:

n=8

Step-by-step explanation:

3n-5=19

3n=19+5

3n=24

n=24/3

n=8

6 0
3 years ago
Point M is the midpoint of AB . AM=3x+3, and AB=8x−6.<br><br> What is the length of AM?
MissTica
AM=3x+3
AB=8x-6
AB=2AM
AM=AB/2
AM=(8x-6)/2
AM=4x-3
3x+3=4x-3
4x-3x=3+3
x=6

AM=3x+3
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AM=18+3
AM=21
6 0
3 years ago
Read 2 more answers
Y=x^2+bx+c;(-2,3)
Maksim231197 [3]
<h3>Answer:  b = 4 and c = 7.</h3>

===============================================

Explanation:

Comparing y = x^2+bx+c to y = ax^2+bx+c, we see that a = 1.

The vertex given is (-2,3). In general, the vertex is (h,k). So h = -2 and k = 3.

Plug those three values into the vertex form below

y = a(x-h)^2 + k

y = 1(x-(-2))^2 + 3

y = (x+2)^2 + 3

Then expand everything out and simplify

y = x^2+4x+4 + 3

y = x^2+4x+7

We see that b = 4 and c = 7.

8 0
3 years ago
Can you help me please
MArishka [77]

Answer:

Step-by-step explanation:

(x^{-2})^3\\\\x^{-2*3}\\\\x^{-6}

(x^3)^2\\\\x^{3*2}\\\\x^6

x^{-2}*x^3\\\\x^{-2+3}\\\\x^1\\\\x

x^2*x^{-3}\\\\x^{2-3}\\\\x^{-1}\\\\\frac{1}{x}

x^2*x^3\\\\x^{2+3}\\\\x^5

Hope this helps!

6 0
3 years ago
Read 2 more answers
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