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sineoko [7]
3 years ago
8

Tom is the deli manager at a grocery store. He needs to schedule employees to staff the deli department at least 260 person-hour

s per week.

Mathematics
1 answer:
marissa [1.9K]3 years ago
5 0
If you would like to find the inequality to determine the number of full-time employees Tom must schedule, you can calculate this using the following steps:

n ... the number of full-time employees

260 <= 20 + n * 40
260 - 20 <= n * 40
240 <= n * 40
n >= 240/40
n >= 6 full-time employees

The correct result would be at least 6 full-time employees.
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Find the sum.<br> (5-21) + (-7+81)
sergij07 [2.7K]
58

First solve what is inside the parentheses (PEMDAS)

(5-21)+(-7+81)
(-16)+(74)
Add
58

Hope this helps! :)
6 0
3 years ago
Read 2 more answers
Plz help me with this now!!
Digiron [165]
The answer will be y=3x-1. You will the steps in the picture

6 0
3 years ago
Im caca at math please help!
Diano4ka-milaya [45]

Answer:

Option B)  \frac{1}{6} Inches

Step-by-step explanation:

Maria's Centipede = 1\frac{1}{12} inches = \frac{13}{12} inches

Jerome Centipede = \frac{11}{12}

<u><em>To see how much longer Maria's centipede was than Jerome's, we'll subtract the two:</em></u>

=> \frac{13}{12} -\frac{11}{12}

=> \frac{13-11}{12}

=> \frac{2}{12} inches

=> \frac{1}{6} Inches

4 0
3 years ago
A karat equals 1/24 part of gold in an alloy [ eg 9 karat gold is 9/24 gold]. How many grams of 9 karat gold must be mixed with
irinina [24]
This is a mixture problem.

Let the 9 karat gold to be mixed be x. The 18 karat would weight (200 - x). Since the total = 200g.

mass1 * karat1 + mass2*karat = total mass * total carat

Let mass1 be x g.          mass 2 would be = (200 -x)
karat 1 = 9                    karat 2 = 18 

Total mass = 200g.
Total karat = 14.

9*x  + 18*(200 -x) = 14*200

9x + 18*200 - 18*x = 14*200

18*200 + 9x - 18x = 14*200

3600 - 9x = 2800

3600 - 2800 = 9x

800 = 9x

9x = 800

x = 800/9

x ≈ 88.89

Therefore 88.89 grams of 9 karat gold must be mixed.
7 0
3 years ago
Which statement is supported by the histograms? The two data sets have the same distribution and same range. The two data sets h
Ad libitum [116K]

Answer:

The two data sets have different distributions and different ranges.

Step-by-step explanation:

When you subtract for both of the ranges they are different numbers. So that's the second part. The numbers along the bottom are different too so that is the different distributions.

5 0
3 years ago
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