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dlinn [17]
3 years ago
12

The explicit rule for a sequence is

Mathematics
2 answers:
Sphinxa [80]3 years ago
6 0
The rule should be a(n)=a(1)+(n-1)d
d=-11 in this case, so a(n)=a(1)-11(n-1)
a(n)=a(1)-11n+11
a(n)=a(1)+11-11n
a(1)+11=48, 
a(1)=37
B is the correct answer. 
pishuonlain [190]3 years ago
3 0
For an explicit formula in its simplified form, we must evaluate the first two terms.

For a_n=48-11n, a_1=48-11=37, and a_2=48-22=26. We see that the common difference is 37-26=-11, and a_1=37, so we write,
a_1=37, \ \ \ a_n=a(n-1)-11. 

The correct answer is B.


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Read 2 more answers
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crimeas [40]

Answer:

Step-by-step explanation:

Let us record the station number 1, 2 or 3 for each family member A, B or C.

I am attaching a table containing total outcomes. Outcomes are presented along rows while the assigned station to each member is written along columns. For ease of understanding, 1 3 2 in the table should be interpreted as family member A being assigned to station 1, member B to station 3 and member C to station number 2, respectively.

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Cases for all members being assigned to same station are as follows:

[1 1 1], [2 2 2], [3 3 3] (outcome number 1, 14 and 27 in the table).

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PROBABILITY\;(Case\;a) = \frac{3}{27}\\\\PROBABILITY\;(Case\;a) = 0.111

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It means that maximum of 2 members can have the same station. Cases for this situation are as follows:

[1 1 2], [1 1 3], [1 2 1], [1 2 2], [1 3 1], [1 3 3], [2 1 1], [2 1 2], [2 2 1], [2 2 3], [2 3 2],

[2 3 3], [3 1 1], [3 1 3], [3 2 2], [3 2 3], [3 3 1], [3 3 2]

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PROBABILITY\;(Case\;b) = \frac{18}{27}\\\\PROBABILITY\;(Case\;b) = 0.666

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For this scenario, we have the following results:

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Therefore,

PROBABILITY\;(Case\;c) = \frac{6}{27}\\\\PROBABILITY\;(Case\;c) = 0.222

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Mandarinka [93]

Answer:

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