Hello! For this problem we need to make use of two existing logarithmic properties. These are:
1.

is equal to

2.

is equal to

Following the first property, we can simplify the expression to

.
Then, we will use the second property to the term 8w. The final form of the expression would then be
ANSWER: 
(second option)
Answer:
diameter 12.81 units to the hundredths
Step-by-step explanation:
Assuming O is the intersection of extensions of PS and QR, at the circumference of T.
PT is chord and TS is perpendicular to PT passing through the centre T. Therefore PS is a perpendicular bisector.
SO = 10/2 = 5
Similarly, RO = 5
Consider right triangle ORT right-angled at R
radius = OT = sqrt(OR^2+RT^2) = sqrt(5^2+4^2) = sqrt(41)
Therefore diameter = 2sqrt(41) = 12.806 (to the third decimal place)
Answer:
5z^2+6a is the answer I think
...........................
Answer:
Its 49
Step-by-step explanation:
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