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9966 [12]
3 years ago
15

Where is the least amount of energy transferred in a food web?

Chemistry
1 answer:
Step2247 [10]3 years ago
5 0

Answer:

From primary consumer to secondary consumer; that is the answer!

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Guys help please!! any five effects of heat!!​
Bogdan [553]

{\huge {\underline {\underline {\bold {\blue{Effects \:  of \:  Heat}}}}}}

  • <em>Expansion </em><em>of </em><em>particles</em><em> </em><em>of</em><em> </em><em>substances.</em><em> </em>
  • <em>Increase</em><em> </em><em>in </em><em>temperature</em><em>.</em>
  • <em>Change</em><em> </em><em>in </em><em>state</em><em>.</em>
  • <em>Change</em><em> </em><em>in </em><em>physical</em><em> </em><em>property</em>
  • <em>It </em><em>may </em><em>bring</em><em> </em><em>out </em><em>chemical</em><em> </em><em>changes</em><em>.</em>

__________________________________

\tt\underline\orange{hope \: it \: helps}

3 0
3 years ago
A) Calculate the average density of the following object (assume it is a perfect sphere). SHOW ALL YOUR WORK (formulas used, num
-BARSIC- [3]

Answers:

A) 2040 kg/m³; B) 58 600 km

Explanation:

A) Density

V = \frac{ 4}{3 }\pi r^{3} = \frac{ 4}{3 }\pi\times (\text{1150 km})^{3} = 6.37 \times 10^{9} \text{ km}^{3}

\text{Density} = \frac{\text{mass}}{\text{volume}} = \frac{1.3\times 10^{22} \text{ kg} }{6.37 \times 10^{9} \text{ km}^{3}}\times (\frac{\text{1 km}}{\text{1000 m}})^{3} = \text{2040 kg/m}^{3}

<em>B) Radius</em>

\text{Volume} = \frac{\text{mass}}{\text{density}} = \frac{5.68\times 10^{26} \text{ kg} }{687 \text{ kg/m}^{3} }= 8.268 \times 10^{23} \text{ m}^{3}

V = \frac{ 4}{3 }\pi r^{3}

r^{3} = \frac{3V }{4 \pi }\

r= \sqrt [3]{ \frac{3V }{4 \pi } }

r= \sqrt [3]{ \frac{3\times 8.268 \times 10^{23} \text{ m}^{3}}{4 \pi } }= \sqrt [3]{ 1.974 \times 10^{23} \text{ m}^{3}}= 5.82 \times 10^{7} \text{ m}=\text{58 200 km}

3 0
3 years ago
How much work does a gas do when it expands against a constant pressure of 0.600 atm from a volume of 50.00 mL to a volume of 44
miskamm [114]

Answer:

23.71J is the work that the gas do.

Explanation:

The work that a gas do under isobaric conditions follows the formula:

W = P*ΔV

<em>Where W is work in atmL, P is the pressure and ΔV is final volume -Initial volume In Liters</em>

Replacing with the values of the problem:

W = P*ΔV

W = 0.600atm*(0.44000L - 0.0500L)

W = 0.234atmL

In Joules (1atmL = 101.325J):

0.234atmL × (101.325J / 1 atmL) =

<h3>23.71J is the work that the gas do.</h3>

<em />

3 0
3 years ago
What are equation for the chemical change that produces water from two hydrogen molecules and one oxygen molecule. And the react
aliya0001 [1]

Answer:

h2+O ---> H2O

reactants: H2 & O

products: H2O

Explanation:

The simple reaction that produces a water molecule from H2 and O would be the one written above, even though there are 2 hydrogen molecules, they will form an H2 molecule rather than 2 individual H molecules (almost never seen) the reactants would be your hydrogen and oxygen molecules individually before they bond to form a molecule of water (H2O) which is the product

6 0
2 years ago
Give the symbol for the element with the following orbital diagram:
wel

Answer: 0%

Explanation:

You got a bad grade

5 0
3 years ago
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