<u>Answer:</u> The molarity of Iron (III) chloride is 0.622 M.
<u>Explanation:</u>
Molarity is defined as the number of moles present in one liter of solution. The equation used to calculate molarity of the solution is:
Or,
We are given:
Mass of iron (III) chloride = 1.01 g
Molar mass of iron (III) chloride = 162.2 g/mol
Volume of the solution = 10 mL
Putting values in above equation, we get:
Hence, the molarity of Iron (III) chloride is 0.622 M.
The electron configuration for magnesium is 1s22s22p63s2
The answer is [OH⁻] = 1 x 10⁻⁸.
To find OH⁻, divide the ionic product of water by [H₃O⁺] as :
<u>OH⁻ + H₃O⁺ = H₂O</u>
<u />
- [OH⁻] = 1 x 10⁻¹⁴ / 1 x 10⁻⁶
- [OH⁻] = 1 x 10⁻⁸
Answer:
Hypochlorous acid - Sodium hypochlorite
Explanation:
A buffer works when pH you want is ± 1 unit of pKa of the buffer. For example, for a buffer with pKa 7, it works between 6 and 8 (7-1 and 7+1).
pKa = -log Ka:
pKa boric acid - Sodium borate: 9.23. As you want a pH of 8.0. This buffer has a pKa too high.
pKa Hypochlorous acid - Sodium hypochlorite: 7.46. With this pKa, this buffer is a great choice to prepare it with a pH = 8.0
pKa Formic acid - Sodium formate: 3.74. This pKa is too low to make a buffer with pH = 8.0
Best choice is:
<h3>Hypochlorous acid - Sodium hypochlorite</h3>