I think its -40 because it looks like you have negative 40 then ur adding 10
Answer:
part a: 52%
part b: 0.4
part c: 0.24
Step-by-step explanation:
For part one, you find the frequency of the number of people that are less that 20. You add the number of tics in each bar and you divide by the total.
so for part a it is (7+6+9+4)/ (7+6+9+4+4+12+8)
for part b you add up the values that are greater than 25(less than 35)
(12+8)/total
part c you find the number of people between 25 and 30
that's 12
over total
12/total
Answer:
0.1507 or 15.07%.
Step-by-step explanation:
We have been given that the manufacturing of a ball bearing is normally distributed with a mean diameter of 22 millimeters and a standard deviation of .016 millimeters. To be acceptable the diameter needs to be between 21.97 and 22.03 millimeters.
First of all, we will find z-scores for data points using z-score formula.
, where,
z = z-score,
x = Sample score,
= Mean,
= Standard deviation.
Let us find z-score of data point 22.03.
Using probability formula , we will get:
Therefore, the probability that a randomly selected ball bearing will be acceptable is 0.1507 or 15.07%.
Answer:
23 is the answer of the question
Answer:
2.5
Step-by-step explanation: