Use the scale factor to find the area of the enlarged figure. Explain your steps.

Mathematics

2 answers:

wariber [46]3 years ago

8 0

Well if you divide 25.6 by 8 and then multiply four by that answer then you have the answer for a, so 4 times 3.2=12.8 , and then you would multiply 25.6 and 12.8 which is 327.68

emmasim [6.3K]3 years ago

6 0

12.8 is the answer you first have to divide 25.6 and 4 t get 3.2.

3.2x 4= 12.8

You might be interested in

Carol, Ann, and Liz each bought a toy fish. Carol's fish is 5 inches longer than Ann's fish. Liz's fish is 9 inches longer than

hram777 [196]

Answer:

The length of Ann's toy fish is 12 inches; the length of Carol's toy fish is 17 inches; and the length of Liz's toy fish is 33 inches.

Step-by-step explanation:

Let's say Carol's fish is c inches long, Ann's is a inches long, and Liz's is l inches long. Then:

c = 5 + a

l = 9 + 2a

a = 12

Plug 12 in for a to find c and l:

c = 5 + a = 5 + 12 = 17 inches

l = 9 + 2a = 9 + 2 * 12 = 9 + 24 = 33 inches

Thus:

The length of Ann's toy fish is 12 inches; the length of Carol's toy fish is 17 inches; and the length of Liz's toy fish is 33 inches.

6 0

2 years ago

Is g h - 5 an expression

Vikki [24]

YES IT IS HOPE IT HELPS YOU ALOT . .
--------

4 0

3 years ago

Which two ordered pairs would represent points on a graph of 5x + 6y = 12?

skelet666 [1.2K]

B. (0,2) and D. (6,-3)

4 0

3 years ago

Sin(60-theta)sin(60+theta)

ehidna [41]

Step-by-step explanation:

$\sin(60 - \theta) \sin(60 + \theta) \\ = \{ \sin(60) \cos( \theta) - \sin( \theta) \cos(60) \} \{ \sin(60) \cos( \theta) + \cos(60) \sin( \theta) \} \\ = \{ \frac{ \sqrt{3} }{2} \cos( \theta) - \frac{1}{2} \sin( \theta) \} \{ \frac{ \sqrt{3} }{2} \cos( \theta) + \frac{1}{2} \sin( \theta) \} \\ \\$

from difference of two squares:

${ \boxed{(a - b)(a + b) = ( {a}^{2} - {b}^{2} ) }}$

therefore:

$= \{ {( \frac{ \sqrt{3} }{2}) }^{2} { \cos }^{2} \theta \} - \{ {( \frac{ \sqrt{3} }{2} )}^{2} { \sin }^{2} \theta \} \\ \\ = \frac{3}{4} { \cos }^{2} \theta - \frac{3}{4} { \sin}^{2} \theta$