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fenix001 [56]
3 years ago
15

Andrea added 0.45 to 0.333 and made the conclusion that the sum of two rational numbers is rational. Is Andrea correct? Explain

Mathematics
1 answer:
Otrada [13]3 years ago
6 0

She's correct, but not for the right reasons. The sum of any two rational numbers <em>is </em>rational, but simply giving one example of that being the case isn't enough. In fact, Andrea could have done <em>billions </em>of similar cases and always found that there was one case she hadn't tested. What we need here is a proof, and here it is.

Let's say we have two rational numbers \frac{a}{b} and \frac{c}{d}, where a, b, c, and d are all integers. Adding the two numbers together, we find that their sum is

\frac{a}{b}+\frac{c}{d}=\frac{a}{b}\big(\frac{d}{d}\big)+\frac{c}{d}\big(\frac{b}{b}\big)=\frac{ad}{bd}+\frac{cb}{bd}=\frac{ad+cb}{bd}

Since the sum or product of any two integers is always another integer, we know that both ad + cb and bd are integers, and since the definition of a rational number is a ratio of two integers, we can say with 100% certainty that \frac{ad+cb}{bd} is rational, which means that <em>the sum of any two rational numbers is also rational</em>.

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s = t + 2/4

Step-by-step explanation:

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A study was conducted to determine whether magnets were effective in treating pain. The values represent measurements of pain us
amm1812

Answer:

Given:

Sham: n= 20,     x=0.44,   s=1.24,

Magnet:n= 20,  x =0.49,   s= 0.95

For Sham:

Sample size, n = 20

Sample mean = 0.44

Standard deviation = 1.24

For Magnet:

Sample size = 20

Sample mean = 0.49

Standard deviation = 0.95

The null and alternative hypotheses:

H0: s1²=s2²

H1: s1² ≠ s2²

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\frac{1.24^2}{0.95^2} = \frac{1.5376}{0.9025} = 1.7037

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b) P-value:

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Magnet: degrees of freedom = n - 1 = 20 - 1 = 19

The critical values:

[Za/2, df1, df2)], [(1 - Za/2), df1, df2]

f[0.05/2, 19, 19], f[(1 - 0.05/2), 19, 19]

f[0.025, 19, 19], f[0.975, 19, 19]

(2.526, 0.3958)

The rejection region:

Reject H0, if  F < 0.3958 or if F > 2.526

c) Conclusion:

Since the critical values of test statistic is between (0.3958 < 1.7037 < 2.526), we fail to reject null hypothesis H0.

There is insufficient evidence to to support the claim that those given a sham treatment have reductions that vary more than those treated with magnets

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Answer:

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First, we realise

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