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den301095 [7]
3 years ago
15

Henrietta is going off to her physics class, jogging down the sidewalk at a speed of 3.95 m/s . Her husband Bruce suddenly reali

zes that she left in such a hurry that she forgot her lunch of bagels, so he runs to the window of their apartment, which is a height 39.9 m above the street level and directly above the sidewalk, to throw them to her. Bruce throws them horizontally at a time 6.50 s after Henrietta has passed below the window, and she catches them on the run. You can ignore air resistance.
Part A

With what initial speed must Bruce throw the bagels so Henrietta can catch them just before they hit the ground?
Engineering
1 answer:
jeka943 years ago
4 0

Answer:

initial speed  = 12.96 m/s

Explanation:

Given data:

speed 3.95 m/s

height = 39.9 m

we know that time to reached the bottom is

H =\frac{1}{2} gt^2

t = \sqrt{\frac{2H}{g}}

= \sqrt{\frac{2\times 39.9}{9.8}}

t = 2.855 sec

total time taken = 2.85 + 6.50 = 9.35 s

total distance at horizontal d = 3.95\times 9.35 = 36.95 m

speed = \frac{d}{t} = \frac{36.95}{2.85} = 12.96 m/s

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