Answer:
Solution:
Note: Refer the diagram
Drag coefficient data for selected objects table at
Hemisphere (open end facing flow), 
Substituting all parameters,
Then,
![\begin{aligned}&V_{b}=V_{w}-\left[\frac{2 F_{R}}{\rho\left(C_{D, w} A_{w}+C_{D, B} A_{b}\right)}\right]^{\frac{1}{2}} \dots\\&V_{w}=24 \times 1000 \times \frac{1}{3600}\\&V_{w}=6.67 \frac{ m }{ s }\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%26V_%7Bb%7D%3DV_%7Bw%7D-%5Cleft%5B%5Cfrac%7B2%20F_%7BR%7D%7D%7B%5Crho%5Cleft%28C_%7BD%2C%20w%7D%20A_%7Bw%7D%2BC_%7BD%2C%20B%7D%20A_%7Bb%7D%5Cright%29%7D%5Cright%5D%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%20%5Cdots%5C%5C%26V_%7Bw%7D%3D24%20%5Ctimes%201000%20%5Ctimes%20%5Cfrac%7B1%7D%7B3600%7D%5C%5C%26V_%7Bw%7D%3D6.67%20%5Cfrac%7B%20m%20%7D%7B%20s%20%7D%5Cend%7Baligned%7D)
And the equation becomes,
![\begin{aligned}&V_{b}=6.67-\left[\frac{2 \times 5.52}{1.23(1.42 \times 1.17+1.2 \times 0.3)}\right]^{\frac{1}{2}}\\&V_{b}=6.67-2.11\\&V_{b}=4.56 \frac{ m }{ s }\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%26V_%7Bb%7D%3D6.67-%5Cleft%5B%5Cfrac%7B2%20%5Ctimes%205.52%7D%7B1.23%281.42%20%5Ctimes%201.17%2B1.2%20%5Ctimes%200.3%29%7D%5Cright%5D%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5C%5C%26V_%7Bb%7D%3D6.67-2.11%5C%5C%26V_%7Bb%7D%3D4.56%20%5Cfrac%7B%20m%20%7D%7B%20s%20%7D%5Cend%7Baligned%7D)
Thus the floyds travels at 
wind speed.
Answer:
Two reasons that justify the requirement for security clearance for aerospace engineers working for government agencies are;
1) Such engineers have access to data regarding the blueprint, components, method of construction, functionality status, new systems design, future systems design, inventory of systems and aeronautical systems database which are sensitive information that are of high importance to the federal government
2) Such engineers take part in the testing of aeronautic equipment, and will require security clearance to be able to input data results into the data base of the aeronautic equipment
Explanation:
