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valina [46]
2 years ago
15

WARNING: when people put links in the answer it is a virus DO NOT DOWNLOAD IT

Engineering
2 answers:
inn [45]2 years ago
8 0
Thank youuuu!!!!!!!!!!!!
kobusy [5.1K]2 years ago
6 0

Answer:

Thank you for this!

Explanation:

I was about to click it on a question I saw.

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The combustion chamber has different shapes depending on the make and model of the engine. True or false
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Do you think that individuals with the same disabilities have the same needs? If your answer is yes, how? /No, why?​
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3 0
2 years ago
A lake with an area of 525 [acre] was monitored during a one-month period. The average inflow was 30 [cfs] for the month and the
Alex73 [517]

Answer:

\Delta S = 1581663.5ft^3

Explanation:

We need to calculate the change in storage through the changes given,

That is,

\Delta S = P+I-O-O_{seepage}-E

Where the loss are representing by,

P= Precipitation\\I= Inflow\\O= Outflow\\O_{Seepage}= Outflow by seepage\\E=Evaporation

So calculating the values we have

\Delta S = P+(I-0)-O_{seepage}-E

\Delta S = 4.25+ (30ft^3/s-27ft^3/s)-1.5in-6in

The values inside the are parenthesis need to be konverted as I note here.

(30days(24hr/1day)(3600s/1hr)(1acre.ft/43560ft^3)(1/525acres)(12in/1ft)

That is,

\Delta S = 0.83in\Delta S= (0.83in*1ft/12in)(525acres)\\\Delta S=36.31 acres.ft\\\Delta S=36.31acres.ft*(43560ft^3/acrees.ft)\\\Delta S = 1581663.5ft^3

3 0
3 years ago
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