Answer:
vapor fraction = 0.4 and 0.08
Explanation:
At reasonably high temperatures, a mixture will exist in the form of a sub cooled liquid. Between these extremes, the mixture exists in a two phrase region where it is a vapor liquid equilibrium. From a vapor-liquid phase diagram, a mixture of 40% A, 39% B, and 21% C separates to give the vapor compositions of 0.4 and 0.08.
Answer:
a) temperature: random error
b) parallax: systematic error
c) using incorrect value: systematic error
Explanation:
Systematic errors are associated with faulty calibration or reading of the equipments used and they could be avoided refining your method.
Answer:
S = 5.7209 M
Explanation:
Given data:
B = 20.1 m
conductivity ( K ) = 14.9 m/day
Storativity ( s ) = 0.0051
1 gpm = 5.451 m^3/day
calculate the Transmissibility ( T ) = K * B
= 14.9 * 20.1 = 299.5 m^2/day
Note :
t = 1
U = ( r^2* S ) / (4*T*<em> t </em>)
= ( 7^2 * 0.0051 ) / ( 4 * 299.5 * 1 ) = 2.0859 * 10^-4
Applying the thesis method
W(u) = -0.5772 - In(U)
= 7.9
next we calculate the pumping rate from well ( Q ) in m^3/day
= 500 * 5.451 m^3 /day
= 2725.5 m^3 /day
Finally calculate the drawdown at a distance of 7.0 m form the well after 1 day of pumping
S = ![\frac{Q}{4\pi T} * W (u)](https://tex.z-dn.net/?f=%5Cfrac%7BQ%7D%7B4%5Cpi%20T%7D%20%2A%20W%20%28u%29)
where : Q = 2725.5
T = 299.5
W(u) = 7.9
substitute the given values into equation above
S = 5.7209 M
Answer:
Web Browser
Explanation:
Because you dont use a messaging app or presentation software to look up stuff its common knowledge