Answer:
y=ax+b
a=-0.6020457867
b=-2.256697516 <------- There is your value for b, which is the answer to the problem.
You can use these values for a and b to generate an equation in slope-intercept form, which you can then enter under Y= and view the graph.
Step-by-step explanation:
What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.
Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy
TE = 0 + 0
∴ TE = 0
The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
Answer:
7 and 6 respectively
Step-by-step explanation:
Firstly, we have to solve the equations simultaneously.
2x + 7p = 56
3x - 11p = -45
Multiply equation I by 3 and ii by 2
6x +21p = 168
6x - 22p = -90
Subtract the second from first to yield:
43p = 258
p = 6
Insert this in equation 1 where we have 2x + 7p = 56
2x + 7(6) =56
2x + 42 = 56
2x = 14 and x = 7
The equilibrium price is 6 and the equilibrium quantity is 7
Answer:
<em>-</em><em>2</em><em>2</em><em> </em><em>/</em><em>3</em><em> </em><em>+</em><em> </em><em>(</em><em>-</em><em>9</em><em>4</em><em>/</em><em>5</em><em>)</em><em> </em>
<em>-</em><em>2</em><em>2</em><em>/</em><em>3</em><em> </em><em>+</em><em> </em><em>-</em><em>8</em><em>9</em><em>/</em><em>5</em>
Step-by-step explanation:
<em>-</em><em>1</em><em>1</em><em>0</em><em>/</em><em>1</em><em>5</em><em> </em><em>+</em><em> </em><em>-</em><em> </em><em>2</em><em>5</em><em>7</em><em>/</em><em>1</em><em>5</em>
<em>-</em><em>3</em><em>6</em><em>7</em><em>/</em><em>1</em><em>5</em>
Answer:
8x+8y
Step-by-step explanation:
