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kolezko [41]
3 years ago
10

Consider the wave function y(x)-Find the probability of fi in the range -a

Physics
1 answer:
Lera25 [3.4K]3 years ago
5 0

Answer:(y(x))^{2}

Explanation:

The probability of fi in a range is given by the integral, whose limits are the range limits, of the square of the wave function y(x).

Example:

let's say range [a,b] with wave function y(x), then

Prob(a\leq x\leq  b)=\int\limits^b_a {y(x)^{2} } \, dx

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If energy is continually added to a gas, what will it likely become?
tamaranim1 [39]
The gas will remain a gas and the energy will be transformed into heat raising the temperature
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5 0
3 years ago
A horse pulls on an object with a force of 300 newtons and does 12,000 joules of work. How far was the object moved?
liubo4ka [24]
We know, work done = Force * displacement 
Here, w = 12,000 J
f = 300 N

Substitute their values into the expression:
12,000 = 300 * d
d = 12,000 / 300
d = 120/3
d = 40 m

In short, Your Answer would be 40 meters

Hope this helps!
6 0
3 years ago
What is the critical angle of light traveling from benzene (n=1.501) into air?
Taya2010 [7]
The critical angle formula should be: sin^-1(1/n) 

 where "n" is 1.501 into the air

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4 0
4 years ago
A round pipe of varying diameter carries petroleum from a wellhead to a refinery. At the wellhead, the pipe's diameter is 50.9 c
seraphim [82]

Answer:

Flow rate 2.34 m3/s

Diameter 0.754 m

Explanation:

Assuming steady flow, the volume flow rate along the pipe will always be constant, and equals to the product of flow speed and cross-section area.

The area at the well head is

A = \pi r_w^2 = \pi (0.509/2)^2 = 0.203 m^2

So the volume flow rate along the pipe is

\dot{V} = Av = 0.203 * 11.5 = 2.34 m^3/s

We can use the similar logic to find the cross-section area at the refinery

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The radius of the pipe at the refinery is:

A_r = \pi r^2

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r = \sqrt{0.141} = 0.377m

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6 0
3 years ago
Acceleration involves a change in __________.
uysha [10]

"Acceleration" is any change in speed or direction of motion ...
slowing down, speeding up, or curving away from a straight line.

You and I, and all other students of Physics, must re-educate
people.  We have to tell everyone that 'acceleration' does NOT
mean 'speeding up'.  AND, it doesn't even necessarily mean
any change in speed.

7 0
3 years ago
Read 2 more answers
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