1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rama09 [41]
3 years ago
11

Compare the energy consumption of two commonly used items in the household. calculate the energy used by a 1.20 kw toaster oven,

wtoaster, which is used for 6.20 minutes and then calculate the amount of energy an 11.0 w compact fluorescent light (cfl), wlight, bulb uses when left on for 8.50 hours.
Physics
2 answers:
sergij07 [2.7K]3 years ago
7 0

Toaster oven:

Power: P=1.20 kW

Time: t=6.20 min \cdot \frac{1}{60 min/h}=0.103 h

So, the energy consumed by the oven is

E=Pt=(1.20 kW)(0.103 h)=0.124 kWh


Fluorescent light:

Power: P=11.0 W=0.011 kW

Time: t=8.50 h

So, the energy consumed by the light is

E=Pt=(0.011 kW)(8.50 h)=0.094 kWh


So, the toaster oven has consumed more energy than the fluorescent light.

slamgirl [31]3 years ago
5 0
<span>we know energy = power*time(in hour) so energy used by 1.20kw(1200 watt) toast oven used for 6.2 min(6.2/60 hour) = 1200*(6.2/60)=1200*0.103 = 124 watt hour. Energy used by 11 w cfl used for 8.50 hour = (11*8) + (11* (50/60)) = 88+9.166=97.166 watt hour.</span>
You might be interested in
How does a lever work?(awarding 24pts for immediate answer!!!!)
vlada-n [284]
It's a simple machine, consisting of a rigid bar that rotates about a fixed point which is known as "Fulcrum" (most important part), It <span>affects the effort, or force and do the amount of work

Hope this helps!</span>
6 0
3 years ago
Read 2 more answers
An airplane is heading south at a speed of 600km/h. If a wind begins blowing from the southwest at a speed of 100km/h, calculate
Karo-lina-s [1.5K]

Answer:

Here's what I got:

Let's assume that N and E are + directions while S and W are - directions.

Wind is blowing from SW; thus, it is blowing towards NE (or at 45 deg N of E).

Dividing the wind's speed into components:y-component: +70.71 km/h; x-component: +70.71 km/h

Dividing the airplane's speed into components:y-component: -600 km/h; x-component: 0 km/h

Adding the components to get the resulting components:y-component: -529.29 km/h; x-component: +70.71

Using the Pythagorean Theorem to find the resulting speed:v^2 = y^2 + x^2 so v = 533.99 km/h

To find the angle of direction, use arctan (y/x):arctan (529.29/70.71) = 82.39 deg

ANSWER: velocity = 533.99 km/h at 82.39 deg S of E

Explanation:

8 0
3 years ago
The weight of an apple at 4r from earth is of that on earth
iris [78.8K]
W = m.g = weight
g = Gme/Re**2 where G= universal gravitational constant , Re= radius of the earth
me= mass of the earth
therefore it weighs 16 times less
4 0
3 years ago
Read 2 more answers
The instantaneous speed of a particle moving along one straight line is v(t) = ate−6t, where the speed v is measured in meters p
beks73 [17]

Answer:

v_max = (1/6)e^-1 a

Explanation:

You have the following equation for the instantaneous speed of a particle:

v(t)=ate^{-6t}   (1)

To find the expression for the maximum speed in terms of the acceleration "a", you first derivative v(t) respect to time t:

\frac{dv(t)}{dt}=\frac{d}{dt}[ate^{-6t}]=a[(1)e^{-6t}+t(e^{-6t}(-6))]  (2)

where you have use the derivative of a product.

Next, you equal the expression (2) to zero in order to calculate t:

a[(1)e^{-6t}-6te^{-6t}]=0\\\\1-6t=0\\\\t=\frac{1}{6}

For t = 1/6 you obtain the maximum speed.

Then, you replace that value of t in the expression (1):

v_{max}=a(\frac{1}{6})e^{-6(\frac{1}{6})}=\frac{e^{-1}}{6}a

hence, the maximum speed is v_max = ((1/6)e^-1)a

5 0
3 years ago
A 6.00-kg box sits on a ramp that is inclined at 37.0° above the horizontal. the coefficient of kinetic friction between the box
forsale [732]
We need to see what forces act on the box:

In the x direction:

Fh-Ff-Gsinα=ma, where Fh is the horizontal force that is pulling the box up the incline, Ff is the force of friction, Gsinα is the horizontal component of the gravitational force, m is mass of the box and a is the acceleration of the box.

In the y direction:

N-Gcosα = 0, where N is the force of the ramp and Gcosα is the vertical component of the gravitational force. 

From N-Gcosα=0 we get: 

N=Gcosα, we will need this for the force of friction.

Now to solve for Fh:

Fh=ma + Ff + Gsinα,

Ff=μN=μGcosα, this is the friction force where μ is the coefficient of friction. We put that into the equation for Fh.
G=mg, where m is the mass of the box and g=9.81 m/s²

Fh=ma + μmgcosα+mgsinα

Now we plug in the numbers and get:

Fh=6*3.6 + 0.3*6*9.81*0.8 + 6*9.81*0.6 = 21.6 + 14.1 + 35.3 = 71 N

The horizontal force for pulling the body up the ramp needs to be Fh=71 N.
8 0
3 years ago
Other questions:
  • A baseball travels 50 meters in 4 seconds what is the average velocity of the baseball?
    11·1 answer
  • Which of the following air conditions would be least likely to have precipitation 10 pts
    14·1 answer
  • Answer and I will give you brainiliest
    15·2 answers
  • 6. Can an object accelerate, but not speed up or slow down?<br> Explain:
    7·1 answer
  • 20 POINTS 20 POINTS On a bright sunny day you decide to take a walk. You begin at your home and walk 1000 meters to an ice cream
    6·1 answer
  • Ships A and B leave port together. For the next two hours, ship A travels at 40.0 mph in a direction 35.0° west of north while t
    5·1 answer
  • When you stand on tiptoes on a bathroom scale, there is an increase in
    12·1 answer
  • PLEASE I NEED HELP
    7·1 answer
  • What is parabolic motion?​
    10·1 answer
  • What is the acceleration of a 100 kg object pushed by Beau with a force of 500 N? Write out your equation.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!