Answer: (60/13, 6/13)
Concept:
There are three general ways to solve systems of equations:
- Elimination
- Substitution
- Graphing
Here, we are going to use <u>elimination </u>since all the variables are in the corresponding position.
Solve:
<u>Given</u>
<u>Multiply the first equation in order to eliminate [x]</u>
<u>Subtract the second equation from the first equation to eliminate [x]</u>
<u>Divide 13 on both sides</u>
<u>Substitute [y] value in order to get [x] value</u>
4x - y = 18
4x - 6/13 = 18
4x = 18 + 6/13
4x = 240/13
Hope this helps!! :)
Please let me know if you have any questions
Let
N--------> <span>members of the club
we know that
($192/(N+2)=3.20
192=(N+2)*3.20
3.20*N+6.40=192
3.20*N=192-6.40
N=185.60/3.20
N=58
the answer is
58</span>
You can make a proportion
<em>Cross multiply</em>
8 × 6 = 48
<em>Now, divide 48 by 9</em>
48 ÷ 9 = 48/9
x = 48/9
10.5x + 3y = 811.5
x + y = 97
y = 97 - x
3y = 291 - 3x
7.5x + 291 = 811.5
7.5x = 811.5 - 291
x = 520.5 / 7.5
x = 69.4
69 were sold at the original price
Answer:
0.1393 = 13.93% probability that an order of 50 units will have one or more faulty units.
Step-by-step explanation:
Mean for a number of units, which means that the Poisson distribution is used to solve this question.
Poisson Distribution:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
Mean:
3 defective for 1000, how many for 50?
3 - 1000
- 50
Applying cross multiplication:
What is the probability that an order of 50 units will have one or more faulty units?
This is:
In which
0.1393 = 13.93% probability that an order of 50 units will have one or more faulty units.