Answer:
Theoretical yield of tungsten produced = 35.6836915592 ≈ 35. 68 g
Explanation:
The chemical equation can be expressed as follows;
WO3 (s) + 3H2(g) → W(s) + 3 H20(g)
Note that the equation is already balanced.
Molecular Mass of WO3= 183.84 + 15.999 × 3 = 183.84 + 47.997 = 231.837 g
From the equation 1 mole of WO3 reacts with 3 mole of hydrogen molecule.
Molecular mass of tungsten(W) = 183.84 g
1 mole of tungsten was produced from the chemical equation.
WO3 (s) + 3H2(g) → W(s) + 3 H20(g)
From the equation,
231. 837 g of WO3 produces 183.84 g of tungsten
45.0 g of WO3 will produce ?
grams of tungsten produced = 183.84 × 45 /231.837
grams of tungsten produced = 8272.8
/231.837
Theoretical yield of tungsten produced = 35.6836915592 ≈ 35. 68 g
The best way to avoid measurement error in an experiment is being shown in the option C. instrument precision which means that a tool is controlled very carefully in order to get the most accurate result, and the answer for your question is D. misreading the instrument as it is an opposite of what I have just said.
