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trapecia [35]
2 years ago
8

PLSSSSSSSSSSSSS HELPPPPPPPPPPPPPPP

Mathematics
1 answer:
sergeinik [125]2 years ago
4 0
Number one is c
number two is a
number three is d
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Each morning a gardener uses 25 gallons of water from a barrel. Each afternoon, she adds 15 gallons of water to the barrel. By h
mr_godi [17]

Given :

Each morning a gardener uses 25 gallons of water from a barrel.

Each afternoon, she adds 15 gallons of water to the barrel.

To Find :

By how much has the volume of water in the barrel changed after 5 days.

Solution :

Amount of of water used from the barrel per day is :

A = 25 - 15 gallons

A = 10 gallons

Now, volume of water in the barrel changed after 5 days is :

V = A × 5 gallons

V = 10 × 5 gallons

V = 50 gallons

Therefore, volume of water in barrel is changed by 50 gallons.

3 0
2 years ago
Find the exact value of the remaining trigonometric functions given: Tan x = Undefined Sin x > 0
finlep [7]

Answer:

  • sin(x) = 1
  • cos(x) = 0
  • cot(x) = 0
  • csc(x) = 1
  • sec(x) = undefined

Step-by-step explanation:

The tangent function can be considered to be the ratio of the sine and cosine functions:

  tan(x) = sin(x)/cos(x)

It will be undefined where cos(x) = 0. The values of x where that occurs are odd multiples of π. The smallest such multiple is x=π/2. The value of the sine function there is positive: sin(π/2) = 1.

The corresponding trig function values are ...

  tan(x) = undefined (where sin(x) >0)

  sin(x) = 1

  cos(x) = 0

__

And the reciprocal function values at x=π/2 are ...

  cot(x) = 0 . . . . . . 1/tan(x)

  csc(x) = 1 . . . . . . .1/sin(x)

  sec(x) = undefined . . . . . 1/cos(x)

3 0
2 years ago
Help with number 5 thx
Temka [501]

First, we find the area of the circle.

A = pi * r^2

A = pi * (1 cm)^2

A = pi cm^2

The area of the circle is pi cm^2.

The area of the triangle is also pi cm^2.

Now we use the area of a triangle.

A = (1/2)bh

(1/2)bh = A

(1/2)(3 cm)h = pi cm^2

(3 cm)h = 2pi cm^2

h = (2/3)pi cm

The exact height is \dfrac{2\pi}{3} ~cm

If you want an approximate height, then it is 2.09 cm.

3 0
3 years ago
For f(x) = -4x -9 evaluate for f(6.5)​
kolezko [41]

Answer:

f=−35

Step-by-step explanation:

<em>1.Simplify  4×6.5 to 26</em>

f=-26-9

<em>2. Simplify  -26-9 to  -35</em>

f=-35

7 0
2 years ago
Find the Diameter of the Circle with the following equation. Round to the nearest tenth.
CaHeK987 [17]

Answer:

<em>1</em><em>1</em><em>.</em><em>8</em><em> </em><em>uni</em><em>ts</em>

Step-by-step explanation:

<em>The circle equation is given as:</em>

<em>The circle equation is given as:(x - 2)^2 + (y + 6)^2 = 35</em>

<em>The circle equation is given as:(x - 2)^2 + (y + 6)^2 = 35A circle equation is represented as:</em>

<em>The circle equation is given as:(x - 2)^2 + (y + 6)^2 = 35A circle equation is represented as:(x - a)^2 + (y - b)^2 = r^2</em>

<em>The circle equation is given as:(x - 2)^2 + (y + 6)^2 = 35A circle equation is represented as:(x - a)^2 + (y - b)^2 = r^2Where</em>

<em>The circle equation is given as:(x - 2)^2 + (y + 6)^2 = 35A circle equation is represented as:(x - a)^2 + (y - b)^2 = r^2WhereDiameter = 2r</em>

<em>The circle equation is given as:(x - 2)^2 + (y + 6)^2 = 35A circle equation is represented as:(x - a)^2 + (y - b)^2 = r^2WhereDiameter = 2rBy comparing both equations, we have</em>

<em>The circle equation is given as:(x - 2)^2 + (y + 6)^2 = 35A circle equation is represented as:(x - a)^2 + (y - b)^2 = r^2WhereDiameter = 2rBy comparing both equations, we haver^2 = 35</em>

<em>The circle equation is given as:(x - 2)^2 + (y + 6)^2 = 35A circle equation is represented as:(x - a)^2 + (y - b)^2 = r^2WhereDiameter = 2rBy comparing both equations, we haver^2 = 35Take the square root of both sides</em>

<em>The circle equation is given as:(x - 2)^2 + (y + 6)^2 = 35A circle equation is represented as:(x - a)^2 + (y - b)^2 = r^2WhereDiameter = 2rBy comparing both equations, we haver^2 = 35Take the square root of both sidesr = 5.9</em>

<em>The circle equation is given as:(x - 2)^2 + (y + 6)^2 = 35A circle equation is represented as:(x - a)^2 + (y - b)^2 = r^2WhereDiameter = 2rBy comparing both equations, we haver^2 = 35Take the square root of both sidesr = 5.9Multiply by 2</em>

<em>The circle equation is given as:(x - 2)^2 + (y + 6)^2 = 35A circle equation is represented as:(x - a)^2 + (y - b)^2 = r^2WhereDiameter = 2rBy comparing both equations, we haver^2 = 35Take the square root of both sidesr = 5.9Multiply by 22r = 11.8</em>

<em>The circle equation is given as:(x - 2)^2 + (y + 6)^2 = 35A circle equation is represented as:(x - a)^2 + (y - b)^2 = r^2WhereDiameter = 2rBy comparing both equations, we haver^2 = 35Take the square root of both sidesr = 5.9Multiply by 22r = 11.8Hence, the diameter of the circle is 11.8 units</em>

8 0
1 year ago
Read 2 more answers
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