What is the empirical formula for ribose (C5H10O5)?
C. CH20
Answer:
The answer is 37amu
Explanation:
We are given:
Chlorine-35: atomic mass =35 amu and percent abundance =75.5% ≡ 0.755
Chlorine-37: atomic mass = x amu and percent abundance =24.5% ≡ 0.25
From table, relative atomic mass of Chlorine is 35.5
⇒(0.755 × 35) + (24.5 × x) = 35.5
26.402 + 24.5x = 35.5
∴ x = 9.075 ÷ 24.5 = 0.37 ≡ 37.
∴ mass of Chlorine 37 = 37amu
Answer:
OOFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF
Explanation:
IM in 7th dont ask me bro
Answer:
The answer is 39.99711. We assume you are converting between grams NaOH and mole. You can view more details on each measurement unit: molecular weight of NaOH or mol This compound is also known as Sodium Hydroxide.