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gtnhenbr [62]
3 years ago
6

The input force of a pulley system must move 8.0 m to lift a 3000-N engine a distance of 2.0 m. What is the IMA of the system?

Chemistry
1 answer:
Maslowich3 years ago
4 0

To overcome a friction, certain amount of input force is needed, and actual mechanical advantage is difficult to be calculated thus, ideal mechanical advantage or IMA is calculated by taking ratio of input distance and output distance. It is mathematically represented as:

IMA=\frac{d_{i}}{d_{o}}

Here,  d_{i}  is input distance and  d_{o} is output distance.

In the problem, input distance is 8 m and output distance is 2 m thus,

IMA=\frac{d_{i}}{d_{o}}=\frac{8 m}{2 m}=4

Therefore, ideal mechanical advantage or IMA is 4.

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Nitrogen family - 5 valence electrons
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Answer:

  • <u>The elements that belong to the nitrogen family are nitrogen, phosphorus, arsenic, antimonium, bismuth, and moscovium.</u>

Explanation:

<em>Families</em> are group of elements that belong to the same column in the periodic table.

Some families have a well known name. For instance, alkali metals is the family of the elements that belong to the first column: Li, Na, K, Rb, Cs, and Fr (H is an exception, in spite it is in the first column it does not belong to the alkali metals family because it is a nonmetal). Other well known families are alkaline earth metals (column 2), halogens (column 3), and noble gases (column 18).

All the members of a family have the same number of valence electrons, i.e. electrons in the outermost shell.

  • <u>Nitrogen</u>, N, is in the column 15; it has 5 valence electrons, because its outer most shell has configurarion ns²np³ (n is 2 because nitrogen is in the second period).

The other members fo this family with the electron configuration of the outermost shell are:

  • <u>Phosphorus</u>, P, 3s² 3p³ (third period)

  • <u>Arsenic,</u> As, 4s² 4p³ (fourth period)

  • <u>Antimonium</u>, Sb, 5s² 5p³ (fith period)

  • <u>Bismuth</u>, Bi, 6s² 6p³ (sixth period)

  • <u>Moscovium</u>, Mc, 7s² 7p³ (seventh period)

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What is the main advantage of using ethanol
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Answer:

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6 0
3 years ago
I NEED HELP PLEASE!!!! CHEMISTRY QUESTION: If 38 g of Li3P and 15 grams of Al2O3 are reacted, what total mass of products will r
maksim [4K]

Answer:

21.5 g.

Explanation:

Hello!

In this case, since the reaction between the given compounds is:

2Li_3P+Al_2O_3\rightarrow 3Li_2O+2AlP

We can see that according to the law of conservation of mass, which states that matter is neither created nor destroyed during a chemical reaction, the total mass of products equals the total mass of reactants based on the stoichiometric proportions; in such a way, we first need to compute the reacted moles of Li3P as shown below:

n_{Li_3P}^{reacted}=38gLi_3P*\frac{1molLi_3P}{51.8gLi_3P}=0.73molLi_3P

Now, the moles of Li3P consumed by 15 g of Al2O3:

n_{Li_3P}^{consumed \ by \ Al_2O_3}=15gAl_2O_3*\frac{1molAl_2O_3}{101.96gAl_2O_3} *\frac{2molLi_3P}{1molAl_2O_3} =0.29molLi_3P

Thus, we infer that just 0.29 moles of 0.73 react to form products; which means that the mass of formed products is:

m_{Li_2O}=0.29molLi_3P*\frac{3molLi_2O}{2molLi_3P} *\frac{29.88gLi_2O}{1molLi_2O} =13gLi_2O\\\\m_{AlP}=0.29molLi_3P*\frac{2molAlP}{2molLi_3P} *\frac{57.95gAlP}{1molAlP} =8.5gAlP

Therefore, the total mass of products is:

m_{products}=13g+8.5g\\\\m_{products}=21.5g

Which is not the same to the reactants (53 g) because there is an excess of Li₃P.

Best Regards!

7 0
3 years ago
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