1 CH4 + 2 O2 --> 1 CO2 + 2 H2O
Answer:
The ratio of HC2H3O2(aq) in the flask after the addition of 5.0mL of NaOH(aq) to HC2H3O2(aq) in the flask after the addition of 1.0mL of NaOH(aq) is 15 : 19 .
Explanation:
HC2H3O2 is CH₃⁻ COOH, which is also known as Acetic acid.
IUPAC name of this compound is Ethanoic acid.
Acetic acid has a basicity of 1. so there is one acidic hydrogen is acetic acid.
Given that, equivalence point was reached when 20.0mL of NaOH is added.
let the normality of acetic acid is N₁ and that of NaOH is N₂.
volume of acetic acid is V₁ and that of NaOH is V₂.
Equivalence point occurs when, N₁ × V₁ = N₂ × V₂.
⇒ N₁ × V₁ = N₂ × 20.
after the addition of 5.0mL of NaOH(aq), remaining N₁ × V° = N₂ × (20 - 5).
= N₂ × 15.
after the addition of 1.0mL of NaOH(aq), remaining N₁ × Vˣ = N₂ × (20 - 1).
= N₂ × 19.
⇒ V° : Vˣ = 15 : 19 .
⇒
Gravitational force -an attractive force that exists between all objects with mass; an object with mass attracts another object with mass; the magnitude of the force is directly proportional to the masses of the two objects and inversely proportional to the square of the distance between the two objects.
Answer:
The % yield is 56.6 %
Explanation:
This is the reaction:
C₂H₄ + Cl₂ → C₂H₄Cl₂
Molar mass of ethylene gas: 28 g/m
Mol = mass / molar mass
140 g / 28 g/m = 5 moles
Ratio is 1:1, so 5 moles of ethylene produce 5 moles of dichloro ethane.
Molar mass of C₂H₄Cl₂ = 98.9 g/m
Mass of C₂H₄Cl₂ produced = 98.9 g/m . 5 m → 494.5 g
% yield reaction
(280 g / 494.5 g ) . 100 = 56.6%
Answer:
endoplasmic reticulum (ER)
