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n200080 [17]
3 years ago
10

Hydrogen gas can be made by reacting methane (CH4) with high temperature steam: CH4(g) + H2O(g) ---> CO(g) + 3H2(g)

Chemistry
2 answers:
goldenfox [79]3 years ago
8 0

CH4(g) + H2O(g) ---> CO(g) + 3H2(g)


mass of methane CH4 = 256g

molar mass of methane,CH4 = C + 4 H = 16.04g/mol


<u>moles of CH4 </u>

= mass/Molar mass

= 256/16.04

= 15.96 moles CH4


<u>moles of H2 produced</u>

= 15.96 moles CH4 x  <u>    3 moles H2     </u>

                                           1 mol CH4

=  47.88 moles H2


<u>number of H2 molecules produced here </u>


= 47.88 moles H2 x   <u>6.022 x 10²³ molecules</u>

                                             1 mole

= 288.335 x 10²³ H2 molecules  

=    <u>2.88 x 10²⁵  H2 molecules</u>


<u>2.88 x 10²⁵</u><u>  H2 molecules </u> are produced when 256g of methane reacts with steam.

zavuch27 [327]3 years ago
6 0
66.2 kg 1) 25 kg H X (1 mol / 2.016) X (16.043 / 1 mol)= 66.2kg I am sorry if this is not what you looking for my friend
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You have 1.0 mole of each compound below. which has the greatest mass?
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What mass of HgO is required to produce 0.692 mol of O2?<br><br>2HgO(s) -&gt; 2Hg(l) + O2(g)
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The answer for the following problem is mentioned below.

  • <u><em>Therefore 298.44 grams of mercuric oxide is needed to produce 0.692 moles of oxygen molecule </em></u>

Explanation:

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no of moles of the oxygen gas = 0.692

Also given:

2 HgO  → 2 Hg + O_{2}

where,

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Hg represents mercury

O_{2} represents oxygen

To calculate:

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          = \frac{2*216*0.692}{1}

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<u />

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