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Vadim26 [7]
4 years ago
13

In what processes do proteins in the electron transport chain participate?

Physics
1 answer:
Shalnov [3]4 years ago
8 0

Answer:

1.Oxidation - reduction reactions and proton pumping

2. Phosphorylation reactions and proton pumping

Explanation:

In oxidative phosphorylation, electrons are transferred from donors to acceptors, that is redox reaction.

These redox reactions release energy, which is used to form ATP. In eukaryotes, these redox reactions are carried out by protein complexes within cell's mitochondria, whereas, in prokaryotes, these proteins are located in the cells' intermembrane space. These linked sets of proteins are called electron transport chains.

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What is sound meaning in science
Sindrei [870]
I<span>n physics, </span>sound<span> is a vibration </span>
3 0
3 years ago
Read 2 more answers
A 2.0-N force acts horizontally on a 10-N block that is initially at rest on a horizontal surface. The coefficient of static fri
Nady [450]

Answer:

None of the statement is false - all of them are true

Explanation:

Let's analyze each statement:

- The net force on the block is zero newtons. --> TRUE. In fact, the block is moving across the surface at constant speed: constant speed means zero acceleration, and according to Newton's second law,

F = ma

this also means a net force of zero newtons.

- The frictional force on the block has magnitude 3.0 N. --> TRUE. The horizontal acceleration of the block is zero, so the resultant of the horizontal forces must be zero:

F-F_f = 0

where F = 3.0 N is the horizontal push and F_f is the frictional force. From the equation, we find

F_f = F = 3.0 N

- The coefficient of kinetic friction between the block and the surface is 0.30. --> TRUE. The frictional force is 3.0 N, and its expression is

F_f = \mu_k (mg)

where \mu_k is the coefficient of kinetic friction and (mg)=10 N is the weight of the block. Solving for \mu_k, we find

\mu_k = \frac{F_f}{mg}=\frac{3 N}{10 N}=0.30

- The direction of the total force that the surface exerts on the block is vertically upward. --> TRUE. Since gravity is acting downward, and the block is not accelerating on the vertical direction neither, there must be an equal and opposite force acting upward on the block: and this force is the force exerted by the surface on the block.

- The block is not accelerated. --> TRUE: the block is moving at constant speed, so its acceleration is zero.

7 0
4 years ago
Displacement vectors of 4 km north, 2 km south, 5 km north, and 5 km south combine to a total displacement of
valentinak56 [21]

south = -(north)

Displacement = (4 km north) + (2 km south) + (5 km north) + (5 km south)

Displacement = (4 km north) - (2 km north) + (5 km north) - (5 km north)

Displacement = (4 - 2 + 5 - 5) km north

<u>Displacement = 2 km north </u>

6 0
3 years ago
Can someone help me please?
Drupady [299]
D is the right answer
5 0
4 years ago
A small mass m slides with negligible friction down an incline at an angle of 25.76° with respect to the horizontal. It then dro
Lunna [17]

• The speed change between T and S is greater between S and R.

• The speed of m at X is  greater that at Q.

• The size of the total force on m at P is less at U.

• The mechanical energy of m at P is equal to that at V.

• The size of the total force on m at S is greater at P.

• The velocity of m at X is equal to that at V.

<h3>What is mechanical energy?</h3>

The mechanical energy is the sum of kinetic energy and the potential energy of an object at any instant of time.

M.E = KE +PE

Given is a small mass m slides with negligible friction down an incline at an angle of 25.76° with respect to the horizontal. It then drops down to a horizontal surface and bounces elastically back up as shown.

The picture shows the position of the mass at equal time intervals starting from rest at T. The height of the mass at X is the same as at V.

Between T to S and S to R, the mass is under constant acceleration. Time taken to move from T to S is greater than S to R. Thus, the speed change between T and S is greater than between S and R.

At Q, there is only a horizontal velocity component, but at X. the speed will be greater and has both vertical and horizontal component. Thus, the speed of m at X is greater than that at Q.

Force is given as the rate of change of momentum with time. At U, change in momentum is large compared to P. Thus, the size of the total force on m at P is less at U.

There is no friction acting on the system. So the energy remains conserved. Mechanical energy at P = V.

The force on mass m at S is only the gravity force. The remaining forces are cancelled by the normal force. Thus, size of the total force on m at S is greater at P.

The energy is conserved at each point of motion of mass. If X and V are at same height, they have same potential energy and so their kinetic energy. Thus, velocity of m at X is equal to that at V.

Learn more about mechanical energy.

brainly.com/question/13552918

#SPJ1

5 0
2 years ago
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