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Alik [6]
3 years ago
13

Is the distance we walk equal to the magnitude of our displacement?

Physics
1 answer:
Yuliya22 [10]3 years ago
8 0

Answer:

If you take the first example of the walk around the desk, it should be apparent that sometimes the distance is the same as the magnitude of the displacement. ... Since the displacement is measured along the shortest path between two points, its magnitude is always less than or equal to the distance.

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What would the electrostatic force be for two 0.005C charges 50m apart?
irakobra [83]

Answer:

90 N

Explanation:

The electrostatic force between two charges is given by:

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1, q2 are the two charges

r is the separation between the charges

In this problem we have

q1 = q2 = 0.005 C

r = 50 m

So the electrostatic force is

F=(9\cdot 10^9 N m^2 C^{-2})\frac{(0.005 C)^2}{(50 m)^2}=90 N

3 0
3 years ago
A homodimeric protein was found to migrate through SDS polyacrilamide gel electrophoresis (SDS-PAGE) with a mobility that matche
disa [49]

Answer:

Adding a reducing agent

Explanation:

Homodimeric proteins are formed by non-covalent interactions between two identical proteins (monomers).

Some of these intermolecular interactions are mediated by disulphide bonds which can be broken by a  reducing agent like beta-mercaptoethanol (2-ME).

By adding the reducing agent to the gel, it is probable that the dimer is broken and the band observed will correspond to the two identical 22.5-kDa monomers.

5 0
3 years ago
On a sunny day, a family decided to take sail on a nearby lake. During sailing the wind applies a force of 25N north on the sail
natka813 [3]

Answer:

its n

Explanation:

4 0
3 years ago
When a hurricane nears land what causes the most damage
amid [387]
A storm surge which is when the winds of the hurricane pull water levels up and cause floods inland
4 0
3 years ago
You are camping with two friends, Joe and Karl. Since all three of you like your privacy, you don't pitch your tents close toget
aleksklad [387]

Answer:

35.7 m

Explanation:

Let

\mid A\mid=18.5 m

\mid B\mid=41 m

We have to find the distance between Joe's and Karl'e tent.

A_x=Acos\theta

A_y=Asin\theta

Substitute the values then we get

A_x=18.5cos23^{\circ}=17 m

A_y=18.5sin 23^{\circ}=7.2 m

B_x=41cos37.5^{\circ}=32.5 m

B_y=41sin37.5^{\circ}=-24.96 m

Because vertical component of B lie in IV quadrant and y-inIV quadrant is negative.

By triangle addition of vector

B=A+C

C=B-A

C_x=B_x-A_x=32.5-17=15.5 m

C_y=B_y-A_y=-24.96-7.2=-32.16\approx=-32.2 m

\mid C\mid=\sqrt{C^2_x+C^2_y}

\mid C\mid=\sqrt{(15.5)^2+(-32.2)^2}=35.7 m

Hence, the distance between Joe's and Karl's tent=35.7 m

6 0
3 years ago
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