Answer:
2144.66 cubic inches
Step-by-step explanation:
The fishbowl is shaped like a sphere the fishbowl has a diameter of 16.
What is the closest value of water in the Fishbowl in cubic inches?
From the any question, we were told to find the closest value of the water in the fishbowl in cubic inches.
This means we are to find the volume.
The volume of a sphere is given as:
4/3πr³
We are given Diameter of the fish bowl = 16 inches
Radius = Diameter/2 = 16 inches/2
= 8 inches
Hence,
Volume of the sphere (Volume of water) = 4/3 × π × 8³
= 2144.66 cubic inches
Answer:
Yes (432 = 9 x48).
Step-by-step explanation:
The trick you need to know is the theorem that says that if the digits in a number add up to a multiple of 9, then the number itself is divisible by 9.
So we go 4+3+2 = 9.
So as this sum of 9 is divisible by 9, it means 432 is also divisible by 9.
If you want to work out the actual answer of 432 divided by 9, you can estimate it by doing 450 ÷ 9 = 50. Then see that 432 is 18 less than 450. And 18 = 2x9. So the answer to the division is 50-2 = 48.
Answer:
25.1 kg
Step-by-step explanation:
A suitable probability calculator can tell you the 5th percentile of this distribution.
9y^3+8y=4y+18y^2
9y^3-18y^2+4y=0
*Divide the whole thing by y
9y^2-18y+4=0
*use quadratic formula to solve
