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3 years ago

Two scientists interpret the same set of data differently. How would the scientific community deal with this problem?

1 answer:

7 0

The correct answer would be D. A new experiment would be needed to be done in order to test the conclusions. In science there is no authority, data is the only thing that matters. So if we have two different conclusions from the same date the only solution is to perform more tests and more experiments to see what is correct.

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A spherical balloon has a radius of 6.95 m and is filled with helium. The density of helium is 0.179 kg/m3, and the density of a

Aleks [24]

volume of balloon

= 4/3 T R3

= 4/3 x 3.14 x 6.953

= 1405.47 m3

uplift force

= volume of balloon x density of air x 9.8

= = 1405.47 x 1.29 x 9.8

= 1813.05 x 9.8 N

weight of helium gas

= volume of balloon x density of helium x

9.8

= 1405.47 x .179 x 9.8

= 251.58 x 9.8 N

Weight of other mass = 930 x 9.8 N Total weight acting downwards

= 251.58 x 9.8 +930 x 9.8

= 1181.58 x 9.8 N

If W be extra weight the uplift can balance

1181.58 × 9.8 + W × 9.8 = 1813.05 * 9.8

1181.58+W=1813.05

W= 631.47 kg

3 0

2 years ago

2+2 can someone plz tell me the pros and cons of ending life right here and now?

kari74 [83]

2+2=4, thx for the pts

8 0

2 years ago

Read 2 more answers

Identify the energy transformation is image below

-BARSIC- [3]

Answer:

chemical to mechanical

hope it helps have a nice day

3 0

2 years ago

You are a member of an alpine rescue team and must get a box of supplies, with mass 3.00 kg , up an incline of constant slope an

Sever21 [200]

Answer:

v = 8.45 m/s

Explanation:

given,

mass = 3 kg

angle = 30.0°

vertical distance = 3.3 m

μ = 0.06

according to conservation of energy

KE(loss) = PE(gain) + Work done (against\ friction)..............(1)

frictional Force

$F_f = \mu N$

$F_f = \mu m g cos \theta$

work against friction

W = F d

$W = \mu m g cos \theta \times h l sin\theta$

$W = \dfrac{\mu m g \times h}{tan\theta}$

Potential energy

PE = mgh

$\dfrac{1}{2}mv^2= \dfrac{\mu mgh}{tan \theta}+ mgh$

$\dfrac{1}{2}v^2= \dfrac{0.06 \times 9.81 \times 3.3}{tan 30^0}+ 9.8\times 3.3$

v = 8.45 m/s

the minimum speed is equal to 8.45 m/s

6 0

3 years ago

Will mark as brainliest . pls help

ipn [44]

Answer:

answer D

Explanation:

circuit breaker is useful when you do something with your domestic electric circuit..

3 0

3 years ago