To solve this problem it is necessary to apply the equations related to the law of Maus.
By the law of Maus we know that
Where,
= Intesity of incident light
I = Intensity of polarized light
With our values we have that
6V/m
Then
Therefore the maximum value of the transmitted E vector is 3V/m
In astronomy circumpolar constellations are those ones which never set from viewer's perspective like ursa minor, cassiopiea etc.
Because of the rotation of the Earth and its orbit around the Sun, we divide the stars and constellations into two groups. Some stars and constellations never rise nor set, and they are called circumpolar. All the rest are divided into seasonal stars and constellations. Which stars and constellations will be circumpolar and which seasonal depends on your latitude.
Answer:
Now e is due to the ring at a
So
We say
1/4πEo(ea/ a²+a²)^3/2
= 1/4πEo ea/2√2a³
So here E is faced towards the ring
Next is E due to a point at the centre
So
E² = 1/4πEo ( e/a²)
Finally we get the total
Et= E²-E
= e/4πEo(2√2-1/2√2)
So the direction here is away from the ring
It’s b all objects with mass experience gravitational attraction I hope this helps
Nitrogen (like70ish % and oxygen like 20%)
