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Andreas93 [3]
4 years ago
14

Explain the application of pascals law​

Physics
1 answer:
Marta_Voda [28]4 years ago
6 0

Answer:

pplications of Pascal’s Law  

Hydraulic Lift: The image you saw at the beginning of this article is a simple line diagram of a hydraulic lift. This is...

The construction is such that a narrow cylinder (in this case A) is connected to a wider cylinder (in this case B). They...

Pressure applied at piston A is transmitted equally to piston B without diminishing, on use of an incompressible fluid.

Explanation:

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1.846....hours

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A circular coil of wire of radius 5.0 cm has 20 turns and carries a current of 2.0 A. The coil lies in a magnetic field of magni
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Answer:a. Magnetic dipole moment is 0.3412Am²

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U = n*I*A

But Area A is given as pi*radius² since it is a circular coil

Radius given is 5cm converting to meter we divide by 100 so we have our radius to be 0.05m. So area A is

A = 3.142*(0.05)² =7.86*EXP {-3} m²

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So magnetic dipole moment U is

U = 20*2*7.86*EXP {-3}=0.3142A.m²

b. Torque is given as the cross product of the magnetic field B and magnetic dipole moment U

Torque = B x U =B*U*Sine(theta)

But since the magnetic field is directed parallel to the plane of the coil from the question, it means that the angle between them is zero and sine zero is equals 0(zero) if you substitute that into the formula for torque you will find out that your torque would equals zero(0)N.m

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State the Newton's law Newton's second law of motion ​
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