Answer:
The magnitude of gravitational force between two masses is 
.
Explanation:
Given that,
Mass of first lead ball, 
Mass of the other lead ball, 
The center of a large ball is separated by 0.057 m from the center of a small ball, r = 0.057 m
We need to find the magnitude of the gravitational force between the masses. It is given by the formula of the gravitational force. It is given by :
So, the magnitude of gravitational force between two masses is . Hence, this is the required solution.
Answer:
water, air, vegetation, and light. also a good temperature thats not too hot or too cold
Explanation:
Answer:
D. half as much
Explanation:
let m and M be the mass of the planets and r be the distance between them.
then: the force of attraction between them is given by,
F = G×m×M/(r^2)
if we keep one mass constant and double the other and also double the distance between them.
the force of attraction becomes:
F1 = 2G×m×M/[(2×r)^2]
= 2G×m×M/[4×(r)^2]
= (1/2)G×m×M/(r^2)
= 1/2×F
therefore, when you double one mass and keep the other mass constant and double the distance between the masses you decrease the force by a factor of 1/2.
Answer:
kinetic energy (K.E) = 5.28 ×10⁻¹⁷
Explanation:
Given:
Mass of α particle (m) = 6.50 × 10⁻²⁷ kg
Charge of α particle (q) = 3.20 × 10⁻¹⁹ C
Potential difference ΔV = 165 V
Find:
kinetic energy (K.E)
Computation:
kinetic energy (K.E) = (ΔV)(q)
kinetic energy (K.E) = (165)(3.20×10⁻¹⁹)
kinetic energy (K.E) = 528 (10⁻¹⁹)
kinetic energy (K.E) = 5.28 ×10⁻¹⁷
