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DedPeter [7]
3 years ago
14

Which expression is equivalent to ^5√32x^5y^10z^15

Mathematics
2 answers:
sattari [20]3 years ago
6 0

\sqrt[5]{32x^5y^{10}z^{15}}=\sqrt[5]{32}\cdot\sqrt[5]{x^5}\cdot\sqrt[5]{(y^2)^5}\cdot\sqrt[5]{(z^3)^5}=2xy^2z^3

Used:

(a^n)^m=a^{n\cdot m}\\\\\sqrt[n]{a^n}=a

Answer: b- 2xy^2z^3

Ulleksa [173]3 years ago
6 0

Answer:  Option 'b' is correct.

Step-by-step explanation:

Since we have given that

^5\sqrt{32x^5y^{10}z^{15}}

We need to find the expression which would be equivalent to the above expression.

As we know that

32=2⁵

So, it becomes,

^5\sqrt{2^5x^5y^{10}z^{15}}\\\\=(2^5)^{\frac{1}{5}}\times (x^5)^{\frac{1}{5}}\times (y^{10}){\frac{1}{5}}\times (z^{15})^{\frac{1}{5}}\\\\=2\times x\times y^2\times z^3\\\\=2xy^2z^3

Hence, Option 'b' is correct.

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Answer:

=1600

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=4*4*4*5*5

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Hope this helps, have a nice day/night! :D

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My sister can walk from school to home in 35 minutes. I can walk from school to home in 20 minutes. But today I stayed for some
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Answer:

you both will reach the home at the same time.

I) You can catch your sister.

ii) Reason: you both will reach home at the same time.

Step-by-step explanation:

Let "d" be distance from school to home.

Let's find the speed of you and your sister.

Speed = \frac{Distance}{Time}

Your speed = \frac{d}{20}

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Remaining distance to reach the home = 1 - \frac{3}{7}d  = \frac{7-3}{7}d = \frac{4}{7}d

=

Now let's find the time to be taken your sister to reach the home.

Time = \frac{distance}{speed}

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So, your sister will take 20 minutes to get home by the time your start.

We know that it takes you 20 minutes to reach your home.

Therefore, you both will reach the home at the same time.

I) You can catch your sister.

ii) Reason: you both will reach home at the same time.

7 0
2 years ago
Anjali's Bikes rents bikes for $15.24 plus $2.61 per hour. Kathryn paid $30.90 to rent a bike. For how many hours did she rent t
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