Answer:
A) 5c = 7.25
(c being the singular lip balm price multiplied by 5)
B) You can draw a picture of 5 Lip balms, label each with (c) and then next to those drawings, put = 7.25. You could also draw 7 dollar bills and a quarter if you wanted!
C) 5c = 7.25
Divide each side by 5
c = 1.45
Each lip balm costs $1.45! Hope this helps! Please award brainliest if helped.
Answer:
25.047 or roughly 25.
Step-by-step explanation:
I solved it wrong the first time then i double check with wolframalpha and got the correct number.
We know that the area of the tile is 18
and it makes a triangle, we also know the base and height. In this case the base is 2
and the height is also given which is
.
Area of triangle =
,
substituting we will end up with 18
=( 2
*
) / 2
Here is the tricky part
, i totally forgot about that lol.
Simplifying: we will get 18
= 
Now, in order to find the x, we will need to take the log of both sides.

Solving for x we end up getting:
= x
where x = 25.047.
To be honest I deserve a nobel prize not a brainliest lol.
Good question bro, take it easy.
1. First, do 12 x 8 to work out the area of the rectangle, which is 96ft.
Then, to work out the area of a circle, you use the equation πr² to help you. You would multiply π by the radius², which is 16. Now you have just worked out the area of a circle, but not a semicircle, so you would have to divide your answer by two to get the area of this, which would be 25.13 (rounded to 2 d.p).
To get the area of the whole shape, you just have to add the two totals together.
25.13 + 96 = 121.13ft.
Remember to put the units there, or you can lose marks.
Try your best with the next questions! I have written the formulas for the other shapes to help you work out the answers.
Area of a square = Multiply sides together.
Area of rectangle = Multiply width by length.
Area of a circle = Multiply π by the radius².
Area of a semicircle = Multiply π by the radius², and the divide by two.
Area of a triangle = Multiply the base by the height, and then divide by two.
Really hope this helps!
Answer:

The maximum width must be 
Step-by-step explanation:
Let
L ----> the length of the rectangular pool
W ---> The width of the rectangular pool
we know that

so
----> inequality A
we have

substitute the value of L in the inequality A

simplify



The maximum width must be 