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Mamont248 [21]
3 years ago
9

A student is trying to calculate the density of a ball. She already knows the mass, but she needs to determine the volume as wel

l. Which of the following formulas can be used to calculate the volume of the ball?
V equals four-thirds times pi times r cubed
V equals one-third times pi times r squared times h
V = s3
V = πr2h
Chemistry
2 answers:
Reptile [31]3 years ago
7 0
Let's examine the given choices:
V = (4/3)*pi*(r)^3 is the rule to calculate the volume of the sphere
V = (1/3)*pi*(r)^2*h is the rule to calculate the volume of the cone
V = s^3 is the rule to calculate volume of the cube
V = pi*(r)^2*h is the rule to calculate volume of the cylinder

Now, the ball can be treated as a perfect sphere, therefore, to calculate its volume we will use the rule of the volume of sphere.

Based on this, the correct choice is:
V = (4/3)*pi*(r)^3
disa [49]3 years ago
7 0

Answer:

A.  V equals four-thirds times pi times r cubed

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1.00 L of a gas at STP is compressed to 473mL. What is the new pressure of gas?
Ratling [72]

Hello!

1.00 L of a gas at STP is compressed to 473 mL. What is the new pressure of gas?

  • <u><em>We have the following data:</em></u>

Vo (initial volume) = 1.00 L  

V (final volume) = 473 mL → 0.473 L  

Po (initial pressure) = 1 atm (pressure exerted by the atmosphere - in STP)  

P (final pressure) = ? (in atm)

  • <u><em>We have an isothermal transformation, that is, its temperature remains constant, if the volume of the gas in the container decreases, so its pressure increases. Applying the data to the equation Boyle-Mariotte, we have:</em></u>

P_0*V_0 = P*V

1*1 = P*0.473

1 = 0.473\:P

0.473\:P = 1

P = \dfrac{1}{0.473}

\boxed{\boxed{P \approx 2.11\:atm}}\:\:\:\:\:\:\bf\green{\checkmark}

<u><em>Answer:  </em></u>

<u><em>The new pressure of the gas is 2.11 atm  </em></u>

___________________________________

\bf\blue{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}

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