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katovenus [111]

3 years ago

8

Y=1/2x+1 and 2y-x=2 the system shown has how many solutions

1 answer:

iren [92.7K]3 years ago

6 0

The answer to the question

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An amount of $19,000 is borrowed for 6 years at 7.25% interest, compounded annually. If the loan is paid in full at the end of t

Galina-37 [17]

The multiplier for increasing by 7.25% is 1.0725. To get our answer we times the price by the multiplier to the power of the amount of years:

19,000 x 1.0725⁶ ( it's to the power of 6 because of the six years)
= 28,915.94
= $28,916 (to the nearest dollar)

So if the loan is to be paid in full the $28,916 (to the nearest dollar) must be paid back.

4 0

3 years ago

MatroZZZ [7]

Answer:

97.5 miles

Step-by-step explanation:

d = 65t

where d is the distance in miles and t is the time in hours

Therefore, to calculate how many miles the car travels in 1.5 hours, substitute t = 1.5 into the equation:

d = 65 x 1.5 = 97.5 miles

5 0

2 years ago

The coefficients of a, b, and c in the following quadratic equation are a = 4, b = 4, and c = -1:

iVinArrow [24]

if c is -1 the equation should be

4x² + 4x -1 = 0

not plus 1

I assume you want the coordinates of the zeros.

if c is indeed -1, they are at (-1.207 , 0) and (0.207 , 0)

if c is +1, as in the equation the only zero point is at (-0.5 , 0)

see screenshot for illustration

5 0

3 years ago

Lim. √2x -√3x-a/√x-√a<br>x approaches a

Ludmilka [50]

Answer: $\sqrt{2}a-\sqrt{3}a-2\sqrt{a}$

Step-by-step explanation:

$\lim _{x\to \:a}\left(\sqrt{2}x-\sqrt{3}x-\frac{a}{\sqrt{x}}-\sqrt{a}\right)$

$=\sqrt{2}a-\sqrt{3}a-\frac{a}{\sqrt{a}}-\sqrt{a}$

$=\sqrt{2}a-\sqrt{3}a-2\sqrt{a}$

3 0

3 years ago

PLZ HELP...Enter in standard form the equation of the line passing through the given point and having the given slope.

Alenkinab [10]

Standard form for the equation of the line is

$$y=-\frac{2}{3} x-\frac{25}{3}$

Solution:

Given point is (2, –5).

slope of the line m = $-\frac{2}{3}$

Here, $x_1=2, y_1=-5$

Equation of a line passing through the point:

$y-y_1=m(x-x_1)$

$$y-(-5)=-\frac{2}{3} (x-(-5))$

$$y+5=-\frac{2}{3} (x+5)$

$$y+5=-\frac{2}{3} x-\frac{10}{3}$

Subtract 15 from both sides of the equation.

$$y+5-5=-\frac{2}{3} x-\frac{10}{3}-5$

$$y=-\frac{2}{3} x-\frac{25}{3}$

Standard form for the equation of the line is

$$y=-\frac{2}{3} x-\frac{25}{3}$

7 0

3 years ago