Answer:
15 have only a dog
5 have a dog and a cat
9 have only a cat
Step-by-step explanation:
20 + 14 = 34, there there are only 29 students, so 34 - 29 or 5 have both a dog and a cat
15 have only a dog
5 have a dog and a cat
9 have only a cat
Change logb24 into logb(8*3).
Next use the product rule to rewrite logb(8*3) as a sum.
logb8 + logb3
Now substitute the values given.
0.71 + 0.23 =
0.94
What I understand is that if this are the three options that you put you should choose X2
13x-6+95=180
Combine like terms
13x=91
Divide by 13
X=7
Two base angles are supplementary/equal 180