What is the factor form of 2x^2-25=0 and -4x^2+81=0

1 answer:

8 0

$2x^2-25=0\\\\(x\sqrt2)^2=5^2=0\\\\(x\sqrt2-5)(x\sqrt2+5)=0\\-------------------------\\-4x^2+81=0\\\\81-4x^2=0\\\\9^2-(2x)^2=0\\\\(9-2x)(9+2x)=0\\------------------------\\Used:\\(a-b)(a+b)=a^2-b^2$

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Hey there!

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f(-3) = 8 ✅

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>> Substitute -3 for x in f(x) :

f(-3) = -(-3) + 5

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Therefore, your answer is f(-3) = 8