Question

How many moles of Cs are contained in 3 moles of Cs3PO4?

Answer 1

Answer:

$\boxed {\boxed {\sf 9 \ moles \ Cs}}$

Explanation:

We are given the compound: Cs₃PO₄

According to the formula, 1 mole of cesium phosphate contains 3 moles of cesium, 1 mole of phosphate, and 4 moles of oxygen.

Therefore, there are 3 moles of cesium for 1 mole of cesium phosphate.

$\frac {3 \ mol \ Cs}{1 \ mol \ Cs_3PO_4}$

We want to calculate the moles of cesium in 3 moles of cesium phosphate, so we multiply the ratio by 3.

$3 \ mol \ Cs_3PO_4 *\frac {3 \ mol \ Cs}{1 \ mol \ Cs_3PO_4}$

$3 *\frac {3 \ mol \ Cs}{1 }= 9 \ mol \ Cs$

3 moles of cesium phosphate contains 9 moles of cesium.