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3 years ago

How many moles of Cs are contained in 3 moles of Cs3PO4?

Chemistry

1 answer:

Alenkinab [10]3 years ago

6 0

Answer:

$\boxed {\boxed {\sf 9 \ moles \ Cs}}$

Explanation:

We are given the compound: Cs₃PO₄

According to the formula, 1 mole of cesium phosphate contains 3 moles of cesium, 1 mole of phosphate, and 4 moles of oxygen.

Therefore, there are 3 moles of cesium for 1 mole of cesium phosphate.

$\frac {3 \ mol \ Cs}{1 \ mol \ Cs_3PO_4}$

We want to calculate the moles of cesium in 3 moles of cesium phosphate, so we multiply the ratio by 3.

$3 \ mol \ Cs_3PO_4 *\frac {3 \ mol \ Cs}{1 \ mol \ Cs_3PO_4}$

$3 *\frac {3 \ mol \ Cs}{1 }= 9 \ mol \ Cs$

3 moles of cesium phosphate contains 9 moles of cesium.

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Vaselesa [24]

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Explanation:

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2 years ago

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3 years ago

Read 2 more answers

What is the solubility of m(oh)2 in a 0.202 m solution of m(no3)2? ksp = 9.05×10−18?

saveliy_v [14]

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3 years ago

A particular reaction, A- products, has a rate that slows down as the reaction proceeds. The half-life of the reaction is found

Thepotemich [5.8K]

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Half life of zero order and second order depends on the initial concentration. But as the given reaction slows down as the reaction proceeds, therefore, it must be second order reaction. This is because rate of reaction does not depend upon the initial concentration of the reactant.

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b. Expression for second order reaction is as follows:

$\frac{1}{[A]} =\frac{1}{[A]_0} +kt$

the above equation can be written in the form of Y = mx + C

so, the plot between 1/[A] and t is linear. So the statement b is true.

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