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tino4ka555 [31]
3 years ago
15

August kekule described the various ring structures of the carbon compound benzene. What type of chemist would he be considered

today? A. Inorganic chemist B. Organic chemist C. Physical chemist D. Biochemist
Chemistry
2 answers:
guapka [62]3 years ago
7 0

Answer:

Organic chemist

Explanation:

Due to catenation property of carbon it is able to form a large number of compounds. To study those compounds, we have classified them as organic compound. The previous definition of organic compound was that the compounds which are obtained from living organism. However after Wholer's synthesis (synthesis of urea from inorganic material) the definition was changed.

so in modern world of chemistry, KeKule (who described the ring structure of benzene) will considered to be an organic chemist as he studied organic compound.

Andreyy893 years ago
3 0
B.  He would be considered an Organic Chemist since Organic Chemistry is the study of Carbon and its compounds.
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They are in order according to their atomic number, so the position should tell you the atomic number. 
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What is the relationship between the density and position of each Earth layer?
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Answer:

The atmosphere and Earth's interior are layered by density. Gravity pulls more strongly on denser materials so denser materials are at the center of things. Earth's core, at its center, is denser than its crust. The lowest layer of the atmosphere is denser than the upper layer.

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3 years ago
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A rigid vessel contains 3.98 kg of refrigerant-134a at 700 kPa and 60°C. Determine the volume of the vessel and the total intern
Arada [10]

<u>Answer:</u> The volume of the vessel is 0.1542m^3 and total internal energy is 162.0 kJ.

<u>Explanation:</u>

  • To calculate the volume of water, we use the equation given by ideal gas, which is:

PV=nRT

or,

PV=\frac{m}{M}RT

where,

P = pressure of container = 700 kPa

V = volume of container = ? L

m = Given mass of R-134a = 3.98 kg = 3980 g    (Conversion factor: 1kg = 1000 g)

M = Molar mass of R-134a = 102.03 g/mol

R = Gas constant = 8.31\text{L kPa }mol^{-1}K^{-1}

T = temperature of container = 60^oC=[60+273]K=333K

Putting values in above equation, we get:

700kPa\times V=\frac{3980g}{102.03g/mol}\times 8.31\text{L kPa }\times 333K\\\\V=154.21L

Converting this value into m^3, we use the conversion factor:

1m^3=1000L

So, \Rightarrow (\frac{1m^3}{1000L})\times 154.21L

\Rightarrow 0.1542m^3

  • To calculate the internal energy, we use the equation:

U=\frac{3}{2}nRT

or,

U=\frac{3}{2}\frac{m}{M}RT

where,

U = total internal energy

m = given mass of R-134a = 3.98 kg = 3980 g  (Conversion factor: 1kg = 1000g)

M = molar mass of R-134a = 102.03 g/mol

R = Gas constant = 8.314J/K.mol

T = temperature = 60^oC=[60+273]K=333K

Putting values in above equation, we get:

U=\frac{3}{2}\times \frac{3980g}{102.03g/mol}\times 8.314J/K.mol\times 333K\\\\U=161994.6J

Converting this into kilo joules, we use the conversion factor:

1 kJ = 1000 J

So, 161994.6 J = 162.0 kJ

Hence, the volume of the vessel is 0.1542m^3 and total internal energy is 162.0 kJ.

6 0
3 years ago
Please help!!! List three different rock cycles for the following: Sedimentary rock, Metamorphic rock, and Igneous rock.
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Sedimentary rocks are formed when different layers of debris ( usually sand ) are forced together under pressure.

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4 years ago
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How many molecules of co2 form when 2.00 g of c2h5oh are produced?
Ronch [10]
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To determine the number of molecules of CO2 that is formed, we need to determine the number of moles produced from the initial amount of C2H5OH and the relation from the reaction. Then we multiply avogadros number which is equal to 6.022x10^23 molecules per mole. 

2.00 g C2H5OH ( 1 mol C2H5OH / 46.08 g C2H5OH ) ( 2 mol CO2 / 1 mol C2H5OH ) = 0.0868 mol CO2
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