Answer:
a) kc = 0,25
b) [A] = 0,41 M
c) [A] = <em>0,8 M</em>
[B] =<em>0,2 M</em>
[C] = <em>0,2M</em>
Explanation:
The equilibrium-constant expression is defined as the ratio of the concentration of products over concentration of reactants. Each concentration is raised to the power of their coefficient.
Also, pure solid and liquids are not included in the equilibrium-constant expression because they don't affect the concentration of chemicals in the equilibrium.
If global reaction is:
A(g) + B(g) ⇋ 2 C(g) + D(s)
The kc = ![\frac{[C]^2}{[A][B]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BC%5D%5E2%7D%7B%5BA%5D%5BB%5D%7D)
a) The concentrations of each compound are:
[A] = 
= <em>0,4 M</em>
[B] = 
= <em>0,1 M</em>
[C] = = <em>0,1 M</em>
<em>kc = </em>![\frac{[0,1]^2}{[0,4][0,1]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5B0%2C1%5D%5E2%7D%7B%5B0%2C4%5D%5B0%2C1%5D%7D)
= 0,25
b) The addition of B and D in the same amount will, in equilibrium, produce these changes:
[A] = 
[B] = 
[C] = 
0,25 = ![\frac{[0,60+2x]^2}{[1,60-x][0,60-x]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5B0%2C60%2B2x%5D%5E2%7D%7B%5B1%2C60-x%5D%5B0%2C60-x%5D%7D)
You will obtain
3,75x² +2,95x +0,12 = 0
Solving
x =-0,74363479081119 → No physical sense
x =-0,043031875855476
Thus, concentration of A is:
= <em>0,41 M</em>
c) When volume is suddenly halved concentrations will be the concentrations in equilibrium over 2L:
[A] = 
= <em>0,8 M</em>
[B] = 
= <em>0,2 M</em>
[C] = = <em>0,2M</em>
I hope it helps!
Answer:
cycloocta-1,4-diene- isolated double bond
cycloocta-1,3-diene- conjugated double bond
cyclodeca-1,2-diene- cumulated double bond
cycloocta-1,3,5,7-tetraene- conjugated double bond
cyclohexa-1,3,5-triene (benzene) - conjugated double bond
penta-1,2,4-triene- cumulated and conjugated double bond
Explanation:
A conjugated double bond is a system that contains alternate double and single bonds. It is renowned for its unusual stability.
A cumulated double bond is a double bond system involving about three atoms e.g C=C=C.
An isolated double bond is a system of double bonds separated by more than one single bond.
Answer : The standard enthalpy of formation of ethylene is, 51.8 kJ/mole
Explanation :
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The formation reaction of 
will be,
The intermediate balanced chemical reaction will be,
(1) 
(2) 
(3) 
Now we will reverse the reaction 1, multiply reaction 2 and 3 by 2 then adding all the equations, we get :
(1) 
(2) 
(3) 
The expression for enthalpy of formation of will be,
Therefore, the standard enthalpy of formation of ethylene is, 51.8 kJ/mole
Answer:
Ammonia contains an asymmetrical distribution of electric charge.
Explanation:
Hello there!
In this case, accordingly to the electronegativity difference we can calculate for the N-H bond, and based off our periodic table, which shows an electronegativity of 3.0 and 2.1 for N and H respectively, we obtain:
Which is within the range of polar molecule even the both of them are nonmetals. Thus, choices a and b are firstly discarded; nonetheless, even when they are both nonmetals, two of these elements usually have a nonpolar bond, which means that option C is discarded, and therefore, our answer is ammonia contains an asymmetrical distribution of electric charge.
Regards!
Answer:15 +18
Explanation:15 fuel +18 oxygen + 33 cd
