No. of moles of calcium chloride = molarity × volume of solution in L
No. of moles of calcium chloride = 2.5 ×0.5 = 1.25 mole
No. of moles of calcium chloride = mass of calcium chloride / molar mass of calcium chloride
1.25 mole = mass of calcium chloride / 110.98 g/mol
mass of calcium chloride = 1.25 ×110.98 = 139 g
Answer:
the sand dune would become flattened and eventually turn into sedementary rock
Answer:
71.7 g of C₆H₅Br are produced at the theoretical yield.
Explanation:
The reaction is:
C₆H₆ + B₂ → C₆H₅Br + HBr
This is an easy excersie, stoichiometry is 1:1
We determine moles of reactants:
42.1 g / 78g/mol = 0.540 moles of benzene
73 g / 159.80 g/mol = 0.457 moles of hydrogen bromide
Certainly, the HBr is the limiting reactant, because I need 0.540 moles of HBr for 0.540 moles of benzene and I only have, 0.457 moles.
0.457 moles of HBr will produce 0.457 of bromobenzene, at the 100 % yield reaction (theoretical yield)
We convert the moles to mass: 0.457 g . 157 g/mol = 71.7 g
Answer:
CLEANER
Explanation:
Independent variable is the variable in an experiment that is changed or manipulated by the experimenter in order to bring about a measurable response.
In this question, Marie notices that the current cleaner she is using on her shower is not cutting through the hard water build-up that has accumulated. She decides to purchase 3 other cleaners to see if one of them will do a better job of cutting through the stains. The CLEANERS being changed in this experiment is the INDEPENDENT VARIABLE.
