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Lemur [1.5K]
2 years ago
10

A solution is prepared by dissolving 51 g of salt in 340 g of

Chemistry
1 answer:
garri49 [273]2 years ago
5 0

Answer:

okķkkkkkkkkkkkkkkkkkkkkk.I don't know the answer. GIVE THANKS

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What is the molecular formula of the structure below?
taurus [48]

Answer:

C₆H₆

Explanation:

Each border of the figure represents 1 atom of carbon. We have 6 borders = 6 atoms of carbon.

Each atom of carbon form 4 bonds. All the carbons are doing a double bond and a single bond with other carbons. That means are bonded 3 times. The other bond (That is not represented in the figure. See the image) comes from hydrogens. As we have 6 carbons that are bonded each 1 with one hydrogen. There are six hydrogens and the molecular formula is:

<h3>C₆H₆</h3>

This structure is: Benzene

8 0
2 years ago
Consider the balanced chemical equation below.
Doss [256]

Answer:

2.33 mol C

Explanation:

Step 1: Write the balanced generic chemical equation

3 A ⟶ C + 4 D

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of A to C is 3:1.

Step 3: Calculate the number of moles of C produced from 7 moles of A

We will use the previously established molar ratio.

7 mol A × 1 mol C/3 mol A = 2.33 mol C

4 0
3 years ago
Please help 20 + points The Law of Conservation of Mass states that matter can neither be ________ nor ___________ in a chemical
Sindrei [870]

The Law of Conservation of Mass states that matter can neither be created nor destroyed in a chemical reaction.

3 0
3 years ago
Read 2 more answers
How many megagrams are in 90.532 g?
Fed [463]
9.0532e-5 should be correct! hope this helps
7 0
2 years ago
How many liters of 1.0 M HCl do you need to neutralize 2.0 L of 3.0 M NaOH? How many liters of 1.0 M HCl do you need to neutrali
Kruka [31]

<u>Answer: </u>

<u>For 1:</u> The volume of HCl required is 6 L.

<u>For 2:</u> The volume of HCl required is 9 L.

<u>For 3:</u> The volume of sulfuric acid required is 4.5 L.

<u>Explanation:</u>

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2        ......(1)

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base

  • <u>For 1:</u>

We are given:

n_1=1\\M_1=1M\\V_1=?L\\n_2=1\\M_2=3.0M\\V_2=2.0L

Putting values in equation 1, we get:

1\times 1\times V_1=1\times 3\times 2\\\\V_1=6L

Hence, the volume of HCl required is 6 L.

  • <u>For 2:</u>

We are given:

n_1=1\\M_1=1M\\V_1=?L\\n_2=2\\M_2=3.0M\\V_2=1.5L

Putting values in equation 1, we get:

1\times 1\times V_1=2\times 3.0\times 1.5\\\\V_1=9L

Hence, the volume of HCl required is 9 L.

  • <u>For 3:</u>

To calculate the volume of acid, we use the equation:

N_1V_1=N_2V_2

where,

N_1\text{ and }V_1 are the normality and volume of acid

N_2\text{ and }V_2 are the normality and volume of base

We are given:

N_1=1.0N\\V_1=?L\\N_2=3.0N\\V_2=1.5L

Putting values in above equation, we get:

1.0\times V_1=3.0\times 1.5\\\\V_1=4.5L

Hence, the volume of sulfuric acid required is 4.5 L.

8 0
3 years ago
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