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SOVA2 [1]
3 years ago
13

You have 1.2 L of air in a balloon 175 K. what is the new volume of the balloon when it is heated to 245 K

Chemistry
1 answer:
Marina86 [1]3 years ago
8 0

Answer:

A) 1.68 L

Explanation:

  • Charles’ Law states that: at constant pressure, the volume is directly proportional to the temperature of the gas.
  • It can be expressed as: V₁T₂ = V₂T₁,

V₁ = 1.2 L, T₁ = 175.0 K, V₂ = ??? L, T₂ = 245.0 K.

∴ V₂ = V₁T₂/T₁ = (1.2 L)(245.0 K)/(175.0 K) = 1.68 L.

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4 years ago
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A Helium gas in a tube with a volume of 9.583 L under pressure of 4.972 atm at 31.8 c
andre [41]

1.905 moles of Helium gas are in the tube. Hence, option A is correct.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Calculate the moles of the gas using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 4.972 atm

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n=?

R= 0.082057338 \;L \;atm \;K^{-1}mol^{-1}

T=31.8 +273= 304.8 K

Putting value in the given equation:

\frac{PV}{RT}=n

n= \frac{4.972 \;atm\; X \;9.583 \;L}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 304.8}

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Learn more about the ideal gas here:

brainly.com/question/27691721

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3 0
2 years ago
A 150.0 mL sample of a 1.50 M solution of CuSO4 is mixed with a 150.0 mL sample of 3.00 M KOH in a coffee cup calorimeter. The t
svp [43]
Mols CuSO4 = M x L = 1.50 x 0.150 = 0.225 
<span>mols KOH = 3.00 x 0.150 = 0.450 </span>
<span>specific heat solns = specific heat H2O = 4.18 J/K*C </span>

<span>CuSO4 + 2KOH = Cu(OH)2 + 2H2O </span>
<span>q = mass solutions x specific heat solns x (Tfinal-Tinitial) + Ccal*deltat T </span>
<span>q = 300g x 4.18 x (31.3-25.2) + 24.2*(31.3-25.2) </span>
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<span>Then convert to kJ/mol


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4 years ago
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