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3 years ago

The following is the question

Physics

1 answer:

andriy [413]3 years ago

5 0

I think either circuit 3 or 2 but I’m pretty sure that it is circuit 2

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Derive mean in science <br>

eduard

Explanation:

derive its name from a Native American word meaning wild onion

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3 years ago

A 2-kg object is moving 6 m/s in a horizontal direction.

german

Answer: A) O N

Explanation:

An object in motion will maintain its state of motion. The presence of an unbalanced force changes the velocity of the object.

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3 years ago

How are color and size related

DiKsa [7]

They’re both describing factors of something

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4 years ago

slader How much energy is required to move a 1040 kg object from the Earth's surface to an altitude four times the Earth's radiu

andrew-mc [135]

Answer:

ΔU = 5.21 × 10^(10) J

Explanation:

We are given;

Mass of object; m = 1040 kg

To solve this, we will use the formula for potential energy which is;

U = -GMm/r

But we are told we want to move the object from the Earth's surface to an altitude four times the Earth's radius.

Thus;

ΔU = -GMm((1/r_f) - (1/r_i))

Where;

M is mass of earth = 5.98 × 10^(24) kg

r_f is final radius

r_i is initial radius

G is gravitational constant = 6.67 × 10^(-11) N.m²/kg²

Since, it's moving to altitude four times the Earth's radius, it means that;

r_i = R_e

r_f = R_e + 4R_e = 5R_e

Where R_e is radius of earth = 6371 × 10³ m

Thus;

ΔU = -6.67 × 10^(-11) × 5.98 × 10^(24)

× 1040((1/(5 × 6371 × 10³)) - (1/(6371 × 10³))

ΔU = 5.21 × 10^(10) J

7 0

3 years ago

An unpolarized beam of light with an intensity of 4000 W/m2 is incident on two ideal polarizing sheets. If the angle between the

erastova [34]

Answer:

The intensity is $I_2 = 1654 \ W/m^2$

Explanation:

From the question we are told that

The intensity of the unpolarized light is $I_o = 4000 \ W/m^2$

The angle between the ideal polarizing sheet is $\theta = 0.429 \ rad = 0.429 * 57.296 = 24.58^o$

Generally the intensity of light emerging from the first polarizer is mathematically represented as

$I_2 = \frac{I_o}{2}$

substituting values

$I_1 = \frac{4000}{2}$

$I_1 = 2000 \ W/m^2$

Then the intensity of incident light emerging from the second polarizer is mathematically represented by Malus law as

$I_2 = I_1 cos^2 (\theta )$

substituting values

$I_2 = 2000 * [cos (24.58)]^2$

$I_2 = 1654 \ W/m^2$

4 0

4 years ago