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dusya [7]
3 years ago
10

The following is the question

Physics
1 answer:
andriy [413]3 years ago
5 0
I think either circuit 3 or 2 but I’m pretty sure that it is circuit 2
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Derive mean in science <br>​
eduard

Explanation:

derive its name from a Native American word meaning wild onion

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3 years ago
A 2-kg object is moving 6 m/s in a horizontal direction.
german

Answer: A) O N

Explanation:

An object in motion will maintain its state of motion. The presence of an unbalanced force changes the velocity of the object.

4 0
3 years ago
How are color and size related
DiKsa [7]
They’re both describing factors of something
5 0
4 years ago
slader How much energy is required to move a 1040 kg object from the Earth's surface to an altitude four times the Earth's radiu
andrew-mc [135]

Answer:

ΔU = 5.21 × 10^(10) J

Explanation:

We are given;

Mass of object; m = 1040 kg

To solve this, we will use the formula for potential energy which is;

U = -GMm/r

But we are told we want to move the object from the Earth's surface to an altitude four times the Earth's radius.

Thus;

ΔU = -GMm((1/r_f) - (1/r_i))

Where;

M is mass of earth = 5.98 × 10^(24) kg

r_f is final radius

r_i is initial radius

G is gravitational constant = 6.67 × 10^(-11) N.m²/kg²

Since, it's moving to altitude four times the Earth's radius, it means that;

r_i = R_e

r_f = R_e + 4R_e = 5R_e

Where R_e is radius of earth = 6371 × 10³ m

Thus;

ΔU = -6.67 × 10^(-11) × 5.98 × 10^(24)

× 1040((1/(5 × 6371 × 10³)) - (1/(6371 × 10³))

ΔU = 5.21 × 10^(10) J

7 0
3 years ago
An unpolarized beam of light with an intensity of 4000 W/m2 is incident on two ideal polarizing sheets. If the angle between the
erastova [34]

Answer:

The intensity is  I_2  =  1654 \ W/m^2

Explanation:

From the question we are told that

    The intensity of the unpolarized light is  I_o  =  4000 \ W/m^2

    The  angle between the ideal polarizing sheet is  \theta =  0.429 \ rad = 0.429 *  57.296 =  24.58^o

Generally the intensity of  light emerging from the first polarizer is mathematically represented as

               I_2  =  \frac{I_o}{2}

substituting values

               I_1  =  \frac{4000}{2}

                I_1  =  2000 \ W/m^2

Then the intensity of  incident light emerging from the second polarizer is mathematically represented by Malus law as

                 I_2  =  I_1  cos^2 (\theta )

substituting values

                I_2  = 2000  * [cos (24.58)]^2

                I_2  =  1654 \ W/m^2

4 0
4 years ago
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