Answer:
z score Perry 
z score Alice 
Alice had better year in comparison with Perry.
Step-by-step explanation:
Consider the provided information.
One year Perry had the lowest ERA of any male pitcher at his school, with an ERA of 3.02. For the males, the mean ERA was 4.206 and the standard deviation was 0.846.
To find z score use the formula.
Here μ=4.206 and σ=0.846
Alice had the lowest ERA of any female pitcher at the school with an ERA of 3.16. For the females, the mean ERA was 4.519 and the standard deviation was 0.789.
Find the z score
where μ=4.519 and σ=0.789
The Perry had an ERA with a z-score is –1.402. The Alice had an ERA with a z-score is –1.722.
It is clear that the z-score value for Perry is greater than the z-score value for Alice. This indicates that Alice had better year in comparison with Perry.
Answer:
The answer is C.
Step-by-step explanation:
I would simplify the expression first.
Equation: (6m^-1)^-3
You can get rid of n^0 because that equals 1.
Any expression raised to the power of -1 equals its reciprocal.
Equation: (6/m)^-3
Equation: (m/6)^3
Final Equation: m^3/216
Now, plug in 3.
(3)^3/216.
27/216 = 1/8
Hope this helps!
This is a division problem. You can use the standard algorithm of 128/ 5. Or you can create equal groups (draw five circles) and count out eggs until you distribute them all. I would start with 20 in each circle. That would be 20+ 20+ 20+ 20+ 20= 100 Then think 128-100= 28 Next count by 5's. 5+ 5+ 5+ 5+ 5= 25 Then think what is 28-25= 3 so 128/ 5= 25 with a reminder of 3 eggs left over.
Answer:
H
Step-by-step explanation:
Out of all of the answers provided, H seems like the equation that makes the most sense.
![[480 - (180)] = 300](https://tex.z-dn.net/?f=%5B480%20-%20%28180%29%5D%20%3D%20300)
Make sure you divide 300 sticks by 60 sticks (box max) to get the number of boxes.
So, Mr. Hanson would need to have 5 more boxes in order to get the total amount of 480 sticks.
From that, H would be considered the best equation that Mr. Hanson would use.
