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elena-s [515]
3 years ago
13

Simplify the expression by combining like terms: 3+ v + 4v2 + 2 - V2 + 3v ]

Mathematics
1 answer:
const2013 [10]3 years ago
7 0

Answer:

I believe the answer would be 3v2+4v+5

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Write an equation of the line in slope-intercept from?
netineya [11]

Answer:

y=-\frac{3}{2}x+2

Step-by-step explanation:

This is for the first question.

Slope-intercept is:

y=mx+b

m - slope

b - y-intercept

We are given the slope of -\frac{3}{2} and a y-intercept of 2.

Plug in the values:

y=mx+b\rightarrow\boxed{y=-\frac{3}{2}x+2}

Hope this helps.

4 0
4 years ago
I'd really appreciate it if anyone could help! :) Giving brainliest.
Naddik [55]

Answer:

A

Step-by-step explanation:

The easiest way to simplify the expression below is using a property: if we take random non-0 number  to the 0 power, we finally get 1, so a^0=1

4 0
4 years ago
Max built a rectangular Prism and a rectangular Pyramid using beach sand. The prism and the pyramid have the same base area and
vova2212 [387]

Answer:

Three times

Step-by-step explanation:

Given

Figures: Rectangular Prism and Rectangular Pyramid

Let the dimension of the prism be:

l = length

w = width

h = height

Amount of sand used is the volume (V1) and it is calculated using;

V_1 = l * w * h

V_1 = lw h

Since the pyramid has the same base area and height as the prism, the its dimension would be:

l = length

w = width

h = height

Amount of sand used is the volume (V2) and it is calculated using;

V_2 = \frac{1}{3}*(lwh)

So, we have:

V_1 = lw h

V_2 = \frac{1}{3}*(lwh)

Substitute lwh for V1 in the second equation

V_2 = \frac{1}{3}V_1

Multiply both sides by 3

3 * V_2 = \frac{1}{3}V_1 * 3

3 * V_2 = V_1

Reorder

V_1 = 3 * V_2

V_1 = 3 V_2

<em>Hence, the amount of sand used in building the prism is three times the amount of sand used in building the pyramid</em>

3 0
3 years ago
Triangle BAC was rotated 90° clockwise and dilated at a scale factor of 2 from the origin to create triangle XYZ. Based on these
ANEK [815]

Answer:

The correct option is;

∠A ≅ ∠X

Step-by-step explanation:

The given coordinates of the points of triangle ACB are;

A(-4, 4), C(-1, 3), B(-4, 0)

The given coordinates of the points of triangle XYZ are;

X(0, 8), Y(8, 8), Z(6, 2), therefore, we have

The length. l. of segment is given by the following formula;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

For the length of the segment AC; (x₁, y₁) = (-4, 4), (x₂, y₂) = (-1, 3), l = √(10)

For the length of the segment AB; (x₁, y₁) = (-4, 4), (x₂, y₂) = (-4, 0), l = 4

For the length of the segment BC; (x₁, y₁) = (-4, 0), (x₂, y₂) = (-1, 3), l = 3·√2

For the length of the segment XY; (x₁, y₁) = (0, 8), (x₂, y₂) = (8, 8), l = 8

For the length of the segment XZ; (x₁, y₁) = (0, 8), (x₂, y₂) = (6, 2), l = 6·√2

For the length of the segment ZY; (x₁, y₁) = (6, 2), (x₂, y₂) = (8, 8), l = 2·√(10

Therefore;

XY ~ AB, XZ ~ BC, ZY ~ AC

Which gives;

∠A ≅ ∠X, ∠B ≅ ∠Y, ∠C ≅ ∠Z

8 0
3 years ago
Read 2 more answers
Express x^2y^2+x^2+y^2+1
Hitman42 [59]

Answer:

( y^2 +1) ( x^2+1)

Step-by-step explanation:

Step 1 ) Factor out x^2 from the expression

x^2 (y^2+1)+y^2+1

Step 2) Factor out y^2 from the expression

(y^2+1) (x^2+1)

Solution is ( y^2 +1) ( x^2+1)

5 0
3 years ago
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