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elena-s [515]
3 years ago
13

Simplify the expression by combining like terms: 3+ v + 4v2 + 2 - V2 + 3v ]

Mathematics
1 answer:
const2013 [10]3 years ago
7 0

Answer:

I believe the answer would be 3v2+4v+5

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Expressing the given functions
OLga [1]
\bf \begin{cases}
f(x)=x^2\\
g(x)=7x-5
\end{cases} \qquad (f\circ g)(x)\iff f(\ g(x)\ )
\\\\\\
f(\ g(x)\ )=[g(x)]^2\implies f(\ g(x)\ )=(7x-5)^2\impliedby h(x)
4 0
3 years ago
Which equation should be used to solve 81 + × =108
Airida [17]
Subtract 81 then divide by that answer.
81+x=108
-81 -81
—————
X=27

The answer’s 27
3 0
3 years ago
Read 2 more answers
Find the probability that the person is frequently or occasionally involved in charity work.
Schach [20]
Given the table below which shows the result of a survey that asked 2,881 people whether they are involved in any type of charity work.

\begin{tabular}
{|c|c|c|c|c|c|}
 &Frequently&Occassionally&Not at all&Total\\[1ex]
Male&227&454&798&1,479\\
Female &205&450&747&1,402\\
Total&432&904&1,545&2,881
\end{tabular}

Part A:

If a person is chosen at random, the probability that the person is frequently or occassinally involved in charity work is given by

P(being \ frequently \ involved \ or \ being \ occassionally \ involved)\\ \\= \frac{432}{2881} + \frac{904}{2881} = \frac{1336}{2881}=\bold{0.464}



Part B:

If a person is chosen at random, the probability that the person is female or not involved in charity work at all is given by

P(being
 \ female \ or \ not \ being \ involved)\\ \\= 
\frac{1402}{2881} + \frac{1545}{2881}-\frac{747}{2881} = 
\frac{2200}{2881}=\bold{0.764}



Part C:

If a person is chosen at random, the probability that the person is male or frequently involved in charity work is given by

P(being
 \ male \ or \ being \ frequently \ involved)\\ \\= 
\frac{1479}{2881} + \frac{432}{2881}-\frac{227}{2881} = 
\frac{1684}{2881}=\bold{0.585}



Part D:

If a person is chosen at random, the probability that the person is female or not frequently involved in charity work is given by

P(being
 \ female \ or \ not \ being \ frequently \ involved)\\ \\= 
\frac{1402}{2881} + \frac{904}{2881} + \frac{1545}{2881}-\frac{450}{2881}-\frac{747}{2881} = 
\frac{2654}{2881}=\bold{0.921}



Part E:

The events "being female" and "being frequently involved in charity work" are not mutually exclusive because being a female does not prevent a person from being frequently involved in charity work.

Indeed from the table, there are 205 females who are frequently involved in charity work.

Therefore, the answer to the question is "No, because 205 females are frequently involved charity work".
4 0
2 years ago
What are the answers please help ?!
mafiozo [28]

Answer:

A, D, E, F

Step-by-step explanation:

Exterior angles are the outer angles.

Angles 5, 6, 2, 3 are all outer angles or exterior angles.

Angles 1 and 4 are interior angles.

7 0
3 years ago
Read 2 more answers
Someone answer 1-8 please! (Please do help!)<br> QUESTION: Find each quotient.
Zinaida [17]
Sorry, but I generally respond to only 1 or 2 problems when someone gives me a long list of homework.  It would take you just a little longer to post one problem at a time.
                                                                             75                 5       -375
Let's look at #5:     75 / (-1/5)   is the same as  -------- = 75 * ------ = ---------                                                                                         -1                -1         1
                                                                              ---
                                                                                5

and this is equivalent to -375 (answer to #5)
6 0
3 years ago
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