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4 years ago

Where is 25/3 on a number line

Mathematics

1 answer:

natka813 [3]4 years ago

7 0

Answer:

25/3 would be after 8, but before 9. It would be twice as close to 8 as it was 9.

Step-by-step explanation:

In order to find this, simply turn the fraction into a mixed number.

25/3 = 8 1/3

So we know it comes 1/3 after 8 and 2/3 before 9

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Pierce is making a rectangular frame for a photo collage that has a perimeter of 72.2 72.2 inches. The length of the frame is 20

Allushta [10]

Answer:

$P = 2x+2y$ (1)

And we know that the lenght is y = 20.3. If we solve for x from equation (1) we got:

$P-2y = 2x$

$\frac{P-2y}{2} =x$

And replacing we got:

$x = \frac{72.2 in -2*20.3 in}{2}= 15.8 in$

And the width for this case would be 15.8 in

Step-by-step explanation:

For this case we know that the photo is rectangular. Let's define:

x = the width, y= the length

And we know that the perimeter is given by:

$P = 2x+2y$ (1)

And we know that the lenght is y = 20.3. If we solve for x from equation (1) we got:

$P-2y = 2x$

$\frac{P-2y}{2} =x$

And replacing we got:

$x = \frac{72.2 in -2*20.3 in}{2}= 15.8 in$

And the width for this case would be 15.8 in

4 0

4 years ago

8x to the 2nd power +2x-3=0

Papessa [141]

Answer:

x= 1/2 and -3/4

Step-by-step explanation:

By using factorization, we can solve this equation.

8x^2+2x-3=0

Factor:

(2x-1)(4x+3)=0

Solve:

2x-1=0

2x=1

x=1/2

Solve again:

4x+3=0

4x=-3

x=-3/4

Hope this helped

5 0

3 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Katena32 [7]

Answer:

(a)

$5^{-3}=\frac{1}{125}$

(b)

$-5^{-3}=-\frac{1}{125}$

(c)

$(-5^{-3})^{-1}=-125$

(d)

$(-5^{-3})^{0}=1$

Step-by-step explanation:

(a)

$5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$5^{-3}=\frac{1}{5^3}$

$5^{-3}=\frac{1}{5\times 5\times 5}$

$5^{-3}=\frac{1}{125}$ ........Answer

(b)

$-5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$-5^{-3}=-\frac{1}{5^3}$

$-5^{-3}=-\frac{1}{5\times 5\times 5}$

$-5^{-3}=-\frac{1}{125}$ ........Answer

(c)

$(-5^{-3})^{-1}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{-1}=(-5)^{-3\times -1}$

$(-5^{-3})^{-1}=(-5)^3$

$(-5^{-3})^{-1}=(-5)\times (-5)\times (-5)$

$(-5^{-3})^{-1}=-125$ ........Answer

(d)

$(-5^{-3})^{0}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{0}=(-5)^{-3\times 0}$

$(-5^{-3})^{-1}=(-5)^0$

we can use property

$a^0=1$

$(-5^{-3})^{0}=1$ ........Answer

4 0

3 years ago

In 25 minutes li can run 10 laps around the track write an equation to represent the relationship

Nonamiya [84]

25 x 10=250 minutes to run.

5 0

3 years ago

A time series that shows a recurring pattern over one year or less is said to follow a Select one:______

zaharov [31]

The answer is C. Seasonal pattern

3 0

4 years ago