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Likurg_2 [28]
3 years ago
14

How do I solve this equation n^2=18n+40.

Mathematics
1 answer:
Readme [11.4K]3 years ago
3 0

Answer:

n = 20 or n = -2

Step-by-step explanation:

Solve for n over the real numbers:

n^2 = 18 n + 40

Subtract 18 n + 40 from both sides:

n^2 - 18 n - 40 = 0

The left hand side factors into a product with two terms:

(n - 20) (n + 2) = 0

Split into two equations:

n - 20 = 0 or n + 2 = 0

Add 20 to both sides:

n = 20 or n + 2 = 0

Subtract 2 from both sides:

Answer:  n = 20 or n = -2

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