The will not affect the wind. When it is windy the wind turns a turbine. Once the wind has gone through the turbine it is just normal wind, none of the wind is lost when this happened
Answer:
Since this is old, im just gonna get these points, don't wan't them to go to waste lm.ao
Explanation:
Answer:
The answer is "
"
Explanation:
Please find the complete question in the attached file.
Equation:
at 
at equilibrium 
![p= 0.47 \ \ atm\\\\SO_2=3.3-0.47 = 2.83 \ \ atm\\\\O_2= 0.74 -\frac{0.47}{2}=0.74-0.235=0.555 \ atm\\\\K_P=\frac{[PSO_3]^2}{[PSO_2]^2[PO_2]}\\\\](https://tex.z-dn.net/?f=p%3D%200.47%20%5C%20%5C%20atm%5C%5C%5C%5CSO_2%3D3.3-0.47%20%3D%202.83%20%5C%20%5C%20atm%5C%5C%5C%5CO_2%3D%200.74%20-%5Cfrac%7B0.47%7D%7B2%7D%3D0.74-0.235%3D0.555%20%5C%20atm%5C%5C%5C%5CK_P%3D%5Cfrac%7B%5BPSO_3%5D%5E2%7D%7B%5BPSO_2%5D%5E2%5BPO_2%5D%7D%5C%5C%5C%5C)
Answer:
Option B. is the right answer.
Explanation:
Before developing a new technology, an engineer has to evaluate the advantages and disadvantages of the chemical used in order to clean water bodies. If the chemical has more disadvantages as compared to advantages, so its usage will be avoided while if the chemical does not harm the marine organisms of the ocean so it can be used for the purpose of cleaning. So we can say that first the engineer has to study the chemicals.
(7.3 x 10^29 atoms) / (24 atoms/molecule) / (6.022 x 10^23 molecules/mol) =
5.1 x 10^4 mol C6H12O6
