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Anvisha [2.4K]
1 year ago
15

If you are traveling at 60mi/hr, how many meters per second is that equivalent to?

Chemistry
1 answer:
lesya [120]1 year ago
5 0

Answer:

26.8224 Meters per Second.      

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Write the formulas for the ionic compounds formed by the following:
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1. KI

2. AlBr₃

3. CsNO₃

4. Al₂(CO₃)₃

Explanation:

1. potassium (K⁺) iodine (I⁻) - KI

2. aluminium (Al³⁺) bromine (Br⁻) - AlBr₃

3. caesium (Cs⁺) nitrate (NO₃⁻) - CsNO₃

4. aluminum (Al³⁺) carbonate (CO₃²⁻)  - Al₂(CO₃)₃

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formulas for the ionic compounds

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You have 100 mL of a solution of benzoic acid in water; the amount of benzoic acid in the solution is estimated to be about 0.30
dimaraw [331]

Answer:

0.00370 g

Explanation:

From the given information:

To determine the amount of acid remaining using the formula:\dfrac{(final \ mass \ of \ solute)_{water}}{(initial \ mass \ of \ solute )_{water}} = (\dfrac{v_2}{v_1+v_2\times k_d})^n

where;

v_1 = volume of organic solvent = 20-mL

n = numbers of extractions = 4

v_2 = actual volume of water = 100-mL

k_d = distribution coefficient = 10

∴

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{100 \ ml}{100 \ ml +20 \ ml \times 10})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{100 \ ml}{100 \ ml +200 \ ml})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{1}{3})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = 0.012345

Thus, the final amount of acid left in the water = 0.012345 * 0.30

= 0.00370 g

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